How do you convert A binary number to a BigInteger in Java?

问题

I needed to convert a very big binary value into its decimal equivalent. As it is a big integer I was using BigInteger. So how do I convert this binary number to a BigInteger?

回答1:

If you have the String representation of your binary number, provide it to this overloaded BigInteger constructor to create an instance:

BigInteger(String val, int radix);

In your case, radix is clearly 2, i.e. you can use something like this:

BigInteger yourNumber = new BigInteger("101000101110...1010", 2);

回答2:

If you have binary String you can convert it to BigInteger like this:

 String binaryString = "1010110101011010101010101101010101100101011010001010001100101110";
 BigInteger bigInt = new BigInteger(binaryString, 2);

回答3:

    String binaryValue = "11111111";
    BigInteger bi = new BigInteger(binaryValue, 2);  

来源：https://stackoverflow.com/questions/17833463/how-do-you-convert-a-binary-number-to-a-biginteger-in-java