Scala ListBuffer (or equivalent) shuffle

问题

Is there a simple shuffle function for Scala lists?

If not, whats the simplest way to implement?

I have a lot of these things to do all over the code, so the simpler the call, the best it is

An example in Ruby

a = [ 1, 2, 3 ]           #=> [1, 2, 3]
a.shuffle                 #=> [2, 3, 1] returns new array shuffled

Thanks in advance :)

回答1:

In Scala you can use scala.util.Random:

util.Random.shuffle((1 to 10).toSeq)
//Vector(9, 6, 8, 7, 10, 1, 2, 5, 3, 4)

util.Random.shuffle(List('A', 'B', 'C', 'D', 'E', 'F'))
//List(B, D, A, E, C, F)

Your results may vary...

来源：https://stackoverflow.com/questions/11040399/scala-listbuffer-or-equivalent-shuffle