How to format var_export to php5.4 array syntax

烈酒焚心 提交于 2019-12-18 12:50:34

问题


There are lots of questions and answers around the subject of valid php syntax from var outputs, what I am looking for is a quick and clean way of getting the output of var_export to use valid php5.4 array syntax.

Given

$arr = [
    'key' => 'value',
    'mushroom' => [
        'badger' => 1
    ]
];


var_export($arr);

outputs

array (
  'key' => 'value',
  'mushroom' => 
  array (
    'badger' => 1,
  ),
)

Is there any quick and easy way to have it output the array as defined, using square bracket syntax?

[
    'key' => 'value',
    'mushroom' => [
        'badger' => 1
    ]
]

Is the general consensus to use regex parsing? If so, has anyone come across a decent regular expression? The value level contents of the arrays I will use will all be scalar and array, no objects or classes.


回答1:


I had something similar laying around.

function var_export54($var, $indent="") {
    switch (gettype($var)) {
        case "string":
            return '"' . addcslashes($var, "\\\$\"\r\n\t\v\f") . '"';
        case "array":
            $indexed = array_keys($var) === range(0, count($var) - 1);
            $r = [];
            foreach ($var as $key => $value) {
                $r[] = "$indent    "
                     . ($indexed ? "" : var_export54($key) . " => ")
                     . var_export54($value, "$indent    ");
            }
            return "[\n" . implode(",\n", $r) . "\n" . $indent . "]";
        case "boolean":
            return $var ? "TRUE" : "FALSE";
        default:
            return var_export($var, TRUE);
    }
}

It's not overly pretty, but maybe sufficient for your case.

Any but the specified types are handled by the regular var_export. Thus for single-quoted strings, just comment out the string case.




回答2:


I realize this question is ancient; but search leads me here. I didn't care for full iterations or using json_decode, so here's a preg_replace-based var_export twister that gets the job done.

function var_export_short($data, $return=true)
{
    $dump = var_export($data, true);

    $dump = preg_replace('#(?:\A|\n)([ ]*)array \(#i', '[', $dump); // Starts
    $dump = preg_replace('#\n([ ]*)\),#', "\n$1],", $dump); // Ends
    $dump = preg_replace('#=> \[\n\s+\],\n#', "=> [],\n", $dump); // Empties

    if (gettype($data) == 'object') { // Deal with object states
        $dump = str_replace('__set_state(array(', '__set_state([', $dump);
        $dump = preg_replace('#\)\)$#', "])", $dump);
    } else { 
        $dump = preg_replace('#\)$#', "]", $dump);
    }

    if ($return===true) {
        return $dump;
    } else {
        echo $dump;
    }
}

I've tested it on several arrays and objects. Not exhaustively by any measure, but it seems to be working fine. I've made the output "tight" by also compacting extra line-breaks and empty arrays. If you run into any inadvertent data corruption using this, please let me know. I haven't benchmarked this against the above solutions yet, but I suspect it'll be a good deal faster. Enjoy reading your arrays!




回答3:


With https://github.com/zendframework/zend-code :

<?php
use Zend\Code\Generator\ValueGenerator;
$generator = new ValueGenerator($myArray, ValueGenerator::TYPE_ARRAY_SHORT);
$generator->setIndentation('  '); // 2 spaces
echo $generator->generate();



回答4:


For anyone looking for a more modern-day solution, use the Symfony var-exporter, also available as a standalone library on composer, but included in Symfony default.

composer require symfony/var-exporter
use Symfony\Component\VarExporter\VarExporter;

// ...

echo VarExporter::export($arr)



回答5:


As the comments have pointed out, this is just an additional syntax. To get the var_export back to the bracket style str_replace works well if there are no ) in the key or value. It is still simple though using JSON as an intermediate:

$output = json_decode(str_replace(array('(',')'), array('&#40','&#41'), json_encode($arr)), true);
$output = var_export($output, true);
$output = str_replace(array('array (',')','&#40','&#41'), array('[',']','(',')'), $output);

I used the HTML entities for ( and ). You can use the escape sequence or whatever.



来源:https://stackoverflow.com/questions/24316347/how-to-format-var-export-to-php5-4-array-syntax

标签
易学教程内所有资源均来自网络或用户发布的内容,如有违反法律规定的内容欢迎反馈
该文章没有解决你所遇到的问题?点击提问,说说你的问题,让更多的人一起探讨吧!