Fix invalid polygon in Shapely

问题

Shapely defines a Polygon as invalid if any of its segments intersect, including segments that are colinear. Many software packages will create a region or area with a "cutout" as shown here which has colinear segments:

>>> pp = Polygon([(0,0), (0,3), (3,3), (3,0), (2,0), 
                  (2,2), (1,2), (1,1), (2,1), (2,0), (0,0)])
>>> pp.is_valid
WARNING:shapely.geos:Self-intersection at or near point 2 0
False

Naturally, the cutout can be implemented natively in Shapely, or this same geometry can be implemented as two valid polygons, but if I only have the list of points shown above, is there an easy to "fix" this (create valid geometry from this list of points)?

回答1:

I found a solution that works for the specific case given:

>>> pp2 = pp.buffer(0)
>>> pp2.is_valid
True
>>> pp2.exterior.coords[:]
[(0.0, 0.0), (0.0, 3.0), (3.0, 3.0), (3.0, 0.0), (2.0, 0.0), (0.0, 0.0)]
>>> pp2.interiors[0].coords[:]
[(2.0, 1.0), (2.0, 2.0), (1.0, 2.0), (1.0, 1.0), (2.0, 1.0)]

来源：https://stackoverflow.com/questions/20833344/fix-invalid-polygon-in-shapely