问题
So if I have a directory stored in a variable, say:
$scriptPath = (Get-ScriptDirectory);
Now I would like to find the directory two parent levels up.
I need a nice way of doing:
$parentPath = Split-Path -parent $scriptPath
$rootPath = Split-Path -parent $parentPath
Can I get to the rootPath in one line of code?
回答1:
Version for a directory
get-item is your friendly helping hand here.
(get-item $scriptPath ).parent.parent
If you Want the string only
(get-item $scriptPath ).parent.parent.FullName
Version for a file
If $scriptPath points to a file then you have to call Directory property on it first, so the call would look like this
(get-item $scriptPath).Directory.Parent.Parent.FullName
Remarks
This will only work if $scriptPath exists. Otherwise you have to use Split-Path cmdlet.
回答2:
I've solved that like this:
$RootPath = Split-Path (Split-Path $PSScriptRoot -Parent) -Parent
回答3:
You can split it at the backslashes, and take the next-to-last one with negative array indexing to get just the grandparent directory name.
($scriptpath -split '\\')[-2]
You have to double the backslash to escape it in the regex.
To get the entire path:
($path -split '\\')[0..(($path -split '\\').count -2)] -join '\'
And, looking at the parameters for split-path, it takes the path as pipeline input, so:
$rootpath = $scriptpath | split-path -parent | split-path -parent
回答4:
You can use
(get-item $scriptPath).Directoryname
to get the string path or if you want the Directory type use:
(get-item $scriptPath).Directory
回答5:
In PowerShell 3, $PsScriptRoot or for your question of two parents up,
$dir = ls "$PsScriptRoot\..\.."
回答6:
You can simply chain as many split-path as you need:
$rootPath = $scriptPath | split-path | split-path
回答7:
Split-Path -Path (Get-Location).Path -Parent
回答8:
To extrapolate a bit on the other answers (in as Beginner-friendly a way as possible):
- String objects that point to valid paths can be converted to DirectoryInfo/FileInfo objects via functions like Get-Item and Get-ChildItem.
- .Parent can only be used on a DirectoryInfo object.
- .Directory converts FileInfo object to a DirectoryInfo object, and will return null if used on any other type (even another DirectoryInfo object).
- .DirectoryName converts a FileInfo object to a String object, and will return null if used on any other type (even another String object).
- .FullName converts a DirectoryInfo/FileInfo object to a String object, and will return null if used on any other type (even another DirectoryInfo/FileInfo object).
Check the object type with the GetType Method to see what you're working with: $scriptPath.GetType()
Lastly, a quick tip that helps with making one-liners: Get-Item has the gi alias and Get-ChildItem has the gci alias.
回答9:
If you want to use $PSScriptRoot you can do
Join-Path -Path $PSScriptRoot -ChildPath ..\.. -Resolve
回答10:
In powershell :
$this_script_path = $(Get-Item $($MyInvocation.MyCommand.Path)).DirectoryName
$parent_folder = Split-Path $this_script_path -Leaf
来源:https://stackoverflow.com/questions/9725521/how-to-get-the-parents-parent-directory-in-powershell