Conditions under which compiler will not define implicits (constructor, destructor, copy constructor, copy assignment) [duplicate]

This is supposed to be a trivial question but I could not find it explicitly on stackoverflow.

The following will be defined implicitly if not provided by the user.

But I have read somewhere (which I cant seem to find now), that there are some conditions where the compiler will not implicitly implement them.

What are these conditions?

The Default Constuctor (e.g., X()) will not be implicitly generated if:

you have explicitly declared any constructor at all
there is a data member that is not default-constructible (such as a reference, a const object, or a class with no or inaccessible default constructor)
(C++11) you have explicitly told the compiler to not generate one using X() = delete;

The Copy Constructor (e.g., X(const X&)) will not be implicitly generated if:

you have explicitly declared a copy constructor (for class X a constructor taking X, X& or const X&)
there is a data member that is not copy-constructible (such as a class with no or inaccessible copy constructor)
the base class is not copy-constructible
(C++11) you have declared a move constructor or move assignment operator
(C++11) you have explicitly told the compiler to not generate one using X(const X&) = delete;

The Copy Assignment Operator (e.g., X& operator=(const X&)) will not be implicitly generated if:

you have explicitly declared a copy assignment operator (for class X an operator= taking X, X& or const X&)
there is a data member in your class that is not copy-assignable (such as a reference, a const object, or a class with no or inaccessible assignment operator)
the base class is not copy-assignable
(C++11) you have declared a move constructor or move assignment operator
(C++11) you have explicitly told the compiler to not generate one using X& operator=(const X&) = delete;

The Destructor (e.g., ~X()) will not be implicitly generated if:

you have explicitly declared a destructor
(C++11) you have explicitly told the compiler to not generate one using ~X() = delete;

The Move Constructor (C++11) (e.g., X(X&&)) will not be implicitly generated if:

you have explicitly declared a move constructor (for class X, a constructor taking X&&)
you have declared a copy assignment operator, copy constructor, destructor, or move assignment operator
there is a data member in your class that cannot be move-constructed (is const, is a reference, or has a deleted, inaccessible, or ambiguous move constructor)
the base class cannot be move-constructed
you have explicitly told the compiler to not generate one using X(X&&) = delete;

The Move Assignment Operator (C++11) (e.g., X& operator=(X&&)) will not be implicitly generated if:

you have explicitly declared a move assignment operator (for class X, an operator= taking X&&)
you have declared a copy assignment operator, copy constructor, destructor, or move constructor
there is a data member in your class that cannot be move-assigned (is const, is a reference, or has a deleted, inaccessible, or ambiguous move assignment operator)
the base class cannot be move-assigned
you have explicitly told the compiler to not generate one using X& operator=(X&&) = delete;

来源：https://stackoverflow.com/questions/15590832/conditions-under-which-compiler-will-not-define-implicits-constructor-destruct

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