问题
I want to get the current date in yyyy-mm-dd hh:mm:ss format.
I have tried:
gmdate('yyyy-mm-dd hh:mm:ss \G\M\T', time());
Its returning a wierd date:
13131313-1111-2323 0707:1111:3131
回答1:
You don't have to repeat those format identifiers . For yyyy you just need to have Y, etc.
gmdate('Y-m-d h:i:s \G\M\T', time());
In fact you don't even need to give it a default time if you want current time
gmdate('Y-m-d h:i:s \G\M\T'); // This is fine for your purpose
Manual
You can get that list of identifiers Here
回答2:
Try this
Check this How do i get the gmt time in php
date_default_timezone_set("UTC");
echo date("Y-m-d H:i:s", time());
回答3:
You had selected the time format wrong
<?php
date_default_timezone_set('GMT');
echo date("Y-m-d,h:m:s");
?>
回答4:
Use below date function to get current time in MySQL format/(As requested on question also)
echo date("Y-m-d H:i:s", time());
回答5:
You are repeating the y,m,d.
Instead of
gmdate('yyyy-mm-dd hh:mm:ss \G\M\T', time());
You should use it like
gmdate('Y-m-d h:m:s \G\M\T', time());
回答6:
gmdate() is doing exactly what you asked for.
Look at formats here: http://php.net/manual/en/function.gmdate.php
来源:https://stackoverflow.com/questions/20159655/how-to-get-gmt-date-in-yyyy-mm-dd-hhmmss-in-php