javascript Hide/show div on checkbox: checked/unchecked

问题

I am trying to make a function in javascript, that will hide / show particular div in my registration form, depending on the state of my checkbox (checked or not). Here is my function:

 function doruc() {
    var elem = document.getElementById('powermail_fieldwrap_331');
        if (document.getElementById  ('powermail_field_doruovaciaadresa2_1').checked) {
        elem.display='block';
        } else {elem.display:none;}
}

It isnt working. I am checking and unchecking my checkbox, but nothing happens. Oh and one more thing. I want that div to be initialized as hidden. Should I put in my css this? :

 #powermail_fieldwrap_331{
 display:none;
 }

I would highly appreciate any suggestions.

回答1:

You could use

var elem = document.getElementById('powermail_fieldwrap_331');
document.getElementById('powermail_field_doruovaciaadresa2_1').onchange = function() {
    elem.style.display = this.checked ? 'block' : 'none';
};

Demo

If you want to hide it by default, you could use #powermail_fieldwrap_331{display:none;}. But if you want to be sure, better use

var elem = document.getElementById('powermail_fieldwrap_331'),
    checkBox = document.getElementById('powermail_field_doruovaciaadresa2_1');
checkBox.checked = false;
checkBox.onchange = function doruc() {
    elem.style.display = this.checked ? 'block' : 'none';
};
checkBox.onchange();

Demo

回答2:

Try this:

elem.style.display='block'

回答3:

You should write it like this :

function doruc() {
var elem = document.getElementById('powermail_fieldwrap_331');
    if (document.getElementById ('powermail_field_doruovaciaadresa2_1').checked) {
    elem.style.display='block';
    } else {elem.style.display='none';}}

and regarding your second question, you can either write in the div tag style="display:none" or you can do as you said (add a class for the element).