问题
AFAIK, C supports just a few data types:
int, float, double, char, void enum.
I need to store a number that could reach into the high 10 digits. Since I'm getting a low 10 digit # from
INT_MAX
, I suppose I need a double.
<limits.h> doesn't have a DOUBLE_MAX. I found a DBL_MAX on the internet that said this is LEGACY and also appears to be C++. Is double what I need? Why is there no DOUBLE_MAX?
回答1:
DBL_MAX is defined in <float.h>. Its availability in <limits.h> on unix is what is marked as "(LEGACY)".
(linking to the unix standard even though you have no unix tag since that's probably where you found the "LEGACY" notation, but much of what is shown there for float.h is also in the C standard back to C89)
回答2:
You get the integer limits in <limits.h> or <climits>. Floating point characteristics are defined in <float.h> for C. In C++, the preferred version is usually std::numeric_limits<double>::max() (for which you #include <limits>).
As to your original question, if you want a larger integer type than long, you should probably consider long long. This isn't officially included in C++98 or C++03, but is part of C99 and C++11, so all reasonably current compilers support it.
回答3:
Its in the standard float.h include file. You want DBL_MAX
回答4:
Using double to store large integers is dubious; the largest integer that can be stored reliably in double is much smaller than DBL_MAX. You should use long long, and if that's not enough, you need your own arbitrary-precision code or an existing library.
回答5:
You are looking for the float.h header.
回答6:
INT_MAX is just a definition in limits.h. You don't make it clear whether you need to store an integer or floating point value. If integer, and using a 64-bit compiler, use a LONG (LLONG for 32-bit).
来源：https://stackoverflow.com/questions/5834635/how-do-i-get-double-max