Finding a public facing IP address in Python?

问题

How can I find the public facing IP for my net work in Python?

回答1:

This will fetch your remote IP address

import urllib
ip = urllib.urlopen('http://automation.whatismyip.com/n09230945.asp').read()

If you don't want to rely on someone else, then just upload something like this PHP script:

<?php echo $_SERVER['REMOTE_ADDR']; ?>

and change the URL in the Python or if you prefer ASP:

<%
Dim UserIPAddress
UserIPAddress = Request.ServerVariables("REMOTE_ADDR")
%>

Note: I don't know ASP, but I figured it might be useful to have here so I googled.

回答2:

whatismyip.org is better... it just tosses back the ip as plaintext with no extraneous crap.

import urllib
ip = urllib.urlopen('http://whatismyip.org').read()

But yeah, it's impossible to do it easily without relying on something outside the network itself.

回答3:

https://api.ipify.org/?format=json is pretty straight forward

can be parsed by just running requests.get("https://api.ipify.org/?format=json").json()['ip']

回答4:

If you don't mind expletives then try:

http://wtfismyip.com/json

Bind it up in the usual urllib stuff as others have shown.

There's also:

http://www.networksecuritytoolkit.org/nst/tools/ip.php

回答5:

import urllib2
text = urllib2.urlopen('http://www.whatismyip.org').read()
urlRE=re.findall('[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}',text)
urlRE        

['146.148.123.123']

Try putting whatever 'findmyipsite' you can find into a list and iterating through them for comparison. This one seems to work well.

回答6:

import requests
r = requests.get(r'http://jsonip.com')
# r = requests.get(r'https://ifconfig.co/json')
ip= r.json()['ip']
print('Your IP is {}'.format(ip))

Reference

回答7:

This is simple as

>>> import urllib
>>> urllib.urlopen('http://icanhazip.com/').read().strip('\n')
'xx.xx.xx.xx'

来源：https://stackoverflow.com/questions/166545/finding-a-public-facing-ip-address-in-python

标签

python

ip-address