How to find nearest next/previous double value (numeric_limits::epsilon for given number)

问题

The title is quite self-explanatory, input is given double value, and I want to add/substract the smallest amount possible.

回答1:

If your compiler implements C99's math functions/C++11, you can use the nextafter:

#include <cfloat> // DBL_MAX
#include <cmath> // std::nextafter

double x = 0.1;

// next representable number after x in the direction of DBL_MAX
double xPlusSmallest = std::nextafter(x, DBL_MAX);

Even if your compiler doesn't support it, it probably has an instrinsic for it. (MSVC has had _nextafter since 2005, for example. GCC probably implements it as standard.)

If your compiler doesn't support it but Boost is available to you, you can do this:

#include <boost/math/special_functions/next.hpp> // boost::float_next

double x = 0.1;

// next representable number after x
double xPlusSmallest = boost::math::float_next(x);

Which is equivalent to this (emulating C99):

#include <boost/math/special_functions/next.hpp> // boost::nextafter
#include <cfloat> // DBL_MAX

double x = 0.1;

// next representable number after x in the direction of DBL_MAX
double xPlusSmallest = boost::math::nextafter(x, DBL_MAX);

And if none of those work for you, you'll just have to crack open the Boost header and copy it.

回答2:

Here's a very dirty trick that isn't actually legal and only works if your platform uses IEEE754 floats: The binary representation of the float is ordered in the same way as the float value, so you can increment the binary representation:

double x = 1.25;

uint64_t * const p = reinterpret_cast<uint64_t*>(&x);

++*p;   // undefined behaviour! but it gets the next value

// now x has the next value

You can achieve the same effect entirely legally by doing the usual binary copy gymnastics to obtain a proper uint64_t value. Make sure to check for zero, infinity and NaN properly, too.

回答3:

How about:

x += fabs(x) * std::numeric_limits<double>::epsilon();

回答4:

#define FLT_MIN         1.175494351e-38F        /* min positive value */
#define FLT_MAX         3.402823466e+38F        /* max value */
#define DBL_MIN         2.2250738585072014e-308 /* min positive value */
#define DBL_MAX         1.7976931348623158e+308 /* max value */

http://xona.com/2006/07/26.html

来源：https://stackoverflow.com/questions/10160079/how-to-find-nearest-next-previous-double-value-numeric-limitsepsilon-for-give

标签

c++

floating-point

double