问题
HTML image elements have this simplified format:
<img src='something'>
That something can be data-uri, for example:
data:image/png;base64,iVBORw0KGg...
Is there a standard way of parsing this with python, so that I get content_type
and base64 data separated, or should I create my own parser for this?
回答1:
Split the data URI on the comma to get the base64 encoded data without the header. Call base64.b64decode
to decode that to bytes. Last, write the bytes to a file.
from base64 import b64decode
data_uri = "data:image/png;base64,iVBORw0KGg..."
header, encoded = data_uri.split(",", 1)
data = b64decode(encoded)
with open("image.png", "wb") as f:
f.write(data)
回答2:
w3lib (a library used by Scrapy) has a function to parse data uris:
>>> from w3lib.url import parse_data_uri
>>> parse_data_uri('data:image/png;base64,iVBORw0KGg==')
ParseDataURIResult(media_type='image/png', media_type_parameters={}, data=b'\x89PNG\r\n\x1a')
回答3:
This may help:
import re
from lxml import html
BASE_NAME = "image_"
source_code = """<img src="data:image/png;base64,iVBORw0KGgoAAAANSUhEUgAAAAUA
AAAFCAYAAACNbyblAAAAHElEQVQI12P4//8/w38GIAXDIBKE0DHxgljNBAAO
9TXL0Y4OHwAAAABJRU5ErkJggg==" alt="Red dot" />
<img src="data:image/gif;base64,R0lGODlhAQABAIAAAAUEBAAAACwAAAAAAQABAAACAkQBADs=" alt="Black dot" />"""
tree = html.fromstring(source_code)
for i,image in enumerate(tree.xpath('//img[contains(@src, "data:image")]/@src')):
image_type, image_content = image.split(',', 1)
image_type = re.findall('data:image\/(\w+);base64', image_type)[0]
with open("{}{}.{}".format(BASE_NAME, i, image_type), "wb") as f:
f.write(image_content.decode('base64'))
print "[*] '{}' image found with content: {}\n".format(image_type, image_content)
Output:
[*] 'png' image found with content: iVBORw0KGgoAAAANSUhEUgAAAAUA
AAAFCAYAAACNbyblAAAAHElEQVQI12P4//8/w38GIAXDIBKE0DHxgljNBAAO
9TXL0Y4OHwAAAABJRU5ErkJggg==
[*] 'gif' image found with content: R0lGODlhAQABAIAAAAUEBAAAACwAAAAAAQABAAACAkQBADs=
It will save every base64
image within <img>
tags, with their respective file extension:
Prefixed by BASE_NAME + auto-increment digit(s) provided by enumerate
+ image_extension
回答4:
Correcting JRodDynamite's post:
from base64 import decodestring
png_arr= "data:image/png;base64,iVBORw0KGg..."
png_arr = png_arr.split(",")
png_arr = png_arr[1]
fh = open("imageToSave.png", "wb")
fh.write(decodestring(png_arr))
fh.close()
回答5:
Python since 3.4 have support for data-uri. Under hood using urllib.request.DataHandler.
from urllib.request import urlopen
with urlopen(data_uri) as response:
data = response.read()
来源:https://stackoverflow.com/questions/33870538/how-to-parse-data-uri-in-python