What does RxJS.Observable debounce do?

喜夏-厌秋 提交于 2019-12-17 19:34:11

问题


Can anybody explain in plain English what RxJS Observavle debounce function does?

I imagine it emits an event once in a while depending on the parameters, but my code below doesn't work as I expected.

var x$ = Rx.Observable.fromEvent(window, 'click')
.map(function(e) {return {x:e.x, y:e.y};})
.debounce(1000)
.subscribe(function(el) {
  console.log(el);
});

and the JsBin version.

I expected that this code would print one click once per second, no matter how fast I am clicking. Instead it prints the click at what I think are random intervals.


回答1:


Debounce will emit a value after a specified time interval has passed without another value being emitted.

Using simple diagrams the following may provide greater help:

Stream 1 | ---1-------2-3-4-5---------6----

    after debounce, the emitted stream looks like as follows:

Stream 2 | ------1-------------5---------6-

The intermediate items (in this case, 2,3,4) are ignored.

An example is illustrated below:

var Rx = require('rx-node');
var source = Rx.fromStream(process.stdin).debounce(500);
var subscription = source.subscribe(
    function (x) {
        console.log('Next: %s', x);
    }
);

I used node to illustrate this... assuming you have node installed, you can run it by typing

$node myfile.js  (where the aforementioned code is in myfile.js)

Once this node program is started you can type values at the console -- if you type quickly items are ignored, and if type intermittently fast and slow items will appear after a gap in typing (in the example above I have 500ms) at the console ("Next: ")

There is also some excellent reference material at https://github.com/Reactive-Extensions/RxJS/blob/master/doc/api/core/operators/debounce.md




回答2:


Long story short: debounce waits for X time that the stream isn't emitting any new value, then let the latest value pass.

Long story: Once a value is emitted, debounce will pause its emission for X time to see if another value is emitted, in fact blocking the stream during this time. If a new value is emitted during the debounce time then the timer is restarted and debounce waits again for the full time. If its timer expires without any new value being emitted, it let the latest value pass.

Let's say that you want to add autocomplete to an input box. If the user insert "a" you may want to show him the choices "acorn, alaska", but if the user right after press "l" you would propose just "alaska". In this case it's better to wait for the user to stop pressing the keyboards to avoid doing unnecessary work. debounce it's the right tool here: it waits for X time the the stream isn't emitting any new value




回答3:


.debounce() produces the last received value if no values were received within the specified interval.

It means that as soon as you click within a second - nothing will be produced.

If you want to throttle values to be emitted no more frequent than every second you need to use .sample(1000) instead.



来源:https://stackoverflow.com/questions/30840247/what-does-rxjs-observable-debounce-do

易学教程内所有资源均来自网络或用户发布的内容,如有违反法律规定的内容欢迎反馈
该文章没有解决你所遇到的问题?点击提问,说说你的问题,让更多的人一起探讨吧!