How to define a default constructor by code using StructureMap?

 ̄綄美尐妖づ 提交于 2019-12-17 19:33:26

问题


I can't figure out how to define the default constructor (when it exists overloads) for a type in StructureMap (version 2.5) by code.

I want to get an instance of a service and the container has to inject a Linq2Sql data context instance into it.

I wrote this in my 'bootstrapper' method :

ForRequestedType<MyDataContext>().TheDefault.Is.OfConcreteType<MyDataContext>();

When I run my app, I got this error :

StructureMap Exception Code: 202
No Default Instance defined for PluginFamily MyNamespace.Data.SqlRepository.MyDataContext, MyNamespace.Data, Version=1.0.0.0, Culture=neutral, PublicKeyToken=null

If I comment out all Linq2Sql generated contructors that I don't need, it works fine.

Update : Oh, and I forgot to say that I would not use the [StructureMap.DefaultConstructor] attribute.


回答1:


You can specify a constructor with the ConstructedBy(). Please try this:

ForRequestedType<MyDataContext>().TheDefault.
Is.ConstructedBy(() => new MyDataContext());

This worked for me.




回答2:


I'm assuming you'd also need to set the object lifetime (InstanceScope) if you are using Linq2Sql. I'd suggest using this code because it give you a little more flexibility.

ForRequestedType< MyDataContext >()
            .CacheBy( InstanceScope.PerRequest )
            .TheDefault.Is.OfConcreteType< MyDataContext >()

SelectConstructor< MyDataContext >( () => new MyDataContext());

With this code you can also further inject interfaces definitions into the MyDataContext constructor like this

SelectConstructor< MyDataContext >( () => new MyDataContext((IDatabaseFactory)null ));

Just remember to define the concrete type with StructureMap for your IDatabaseFactory instance.




回答3:


I'm not sure how / if it can be done with the fluent interface / internal DSL. You can however use an attribute, if you're not fussed about polluting your domain?

Tag your preferred constructor with [DefaultConstructor] StructureMap defaults to the greediest constructor by convention (constructor with the most parameters).



来源:https://stackoverflow.com/questions/289512/how-to-define-a-default-constructor-by-code-using-structuremap

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