Javascript: Sort array of arrays by second element in each inner array

问题

I have an array that looks like this:

const arr = [
  [500, 'Foo'],
  [600, 'bar'],
  [700, 'Baz'],
];

I would like to sort this arr alphabetically by the second element in each inner array, ie:

[
  [600, 'bar'],
  [700, 'Baz'],
  [500, 'Foo'],
]

Note the case insensitivity. Also, I would love to use lodash helpers if they come in handy here!

回答1:

Here is a concrete, working example, using Array.prototype.sort:

const arr = [
  [500, 'Foo'],
  [600, 'bar'],
  [700, 'Baz']
];

arr.sort((a,b) => a[1].toUpperCase().localeCompare(b[1].toUpperCase()));

console.log(arr);

回答2:

Array.prototype.sort takes a function which will be applied to each pair of items in the array. The return of that function determines how the items are sorted (it needs to return a positive number, 0, or a negative number).

来源：https://stackoverflow.com/questions/39583327/javascript-sort-array-of-arrays-by-second-element-in-each-inner-array