How can escape colon in a string within an Ansible YAML file?

问题

I want to change one line of my code in file /var/www/kibana/config.js during installation from

elasticsearch: "http://"+window.location.hostname+":9200"

to

elasticsearch: "http://192.168.1.200:9200"

Here I tried to use lineinfile to do that as show below

- name: Comment out elasticsearch the config.js to ElasticSearch server
  lineinfile:
    dest=/var/www/kibana/config.js
    backrefs=true
    regexp="(elasticsearch.* \"http.*)$"
    line="elasticsearch\: \" {{ elasticsearch_URL }}:{{ elasticsearch_port }} \" "
    state=present

I have set variables of {{elasticsearch_URL}} and {{elasticsearch_port}} to http://192.168.1.200 and 9200, respectively.

Here is the error message I met:

ERROR: Syntax Error while loading YAML script, /Users/shuoy/devops_workspace/ansible_work/logging-for-openstack/roles/kibana/tasks/Debian.yml
Note: The error may actually appear before this position: line 29, column 25

regexp="(elasticsearch.* \"http.*)$"
line="elasticsearch\: \" {{ elasticsearch_URL }}:{{ elasticsearch_port }} \" "
                    ^

回答1:

you need to enclose the entire line in ", where : appears.

lineinfile:
'dest=/var/www/kibana/config.js
backrefs=true
regexp="(elasticsearch.* \"http.*)$"
line="elasticsearch\: \ {{ elasticsearch_URL }}:{{ elasticsearch_port }} \ "
state=present'  

See these pages:
Link-1 Link-2 Link-3

回答2:

The solution that will work in any case no matter how many nested quotes you might have and without forcing you to add more quotes around the whole thing (which can get tricky to impossible depending on the line you want to write) is to output the colon through a Jinja2 expression, which simply returns the colon as a string:

{{ ":" }}

Or in your complete line:

line="elasticsearch\: \" {{ elasticsearch_URL }}{{ ":" }}{{ elasticsearch_port }} \" "

Credit to this goes to github user drewp.

回答3:

Just keep the colon in quotes separately -

regexp="(elasticsearch.* \"http.*)$" line="elasticsearch':' \" {{ elasticsearch_URL }}:{{ elasticsearch_port }} \" "

回答4:

foo=bar is the more suitable format for a one-line directive, but as you're already spanning several lines with your parameters anyway, just change the = to :, and it won't fuss about having a colon in your string.

- name: Comment out elasticsearch the config.js to ElasticSearch server
  lineinfile:
    dest:     /var/www/kibana/config.js
    backrefs: true
    regexp:   'elasticsearch.* "http.*$'
    line:     'elasticsearch: "{{ elasticsearch_URL }}:{{ elasticsearch_port }}"'
    state:    present

回答5:

It’s a string already; you don’t have to (and can’t, as seen here) escape colons inside it.

line="elasticsearch: \" {{ elasticsearch_URL }}:{{ elasticsearch_port }} \" "

来源：https://stackoverflow.com/questions/24835706/how-can-escape-colon-in-a-string-within-an-ansible-yaml-file