Check if an application is idle for a time period and lock it

无人久伴 提交于 2019-12-17 08:53:49

问题


In my project I need an application lock (same as windows lock). If the application is idle for a time period the application should be locked i.e, the login window for the application will appear. How can I do it in a WPF C# application?


回答1:


You can use these functions

  • LockWorkStation
  • GetLastInputInfo

see this code, you must add a timer to your form, and set this.timer1.Enabled = true;

using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Text;
using System.Windows.Forms;
using System.Runtime.InteropServices;

namespace WindowsFormsApplication9
{
  internal struct LASTINPUTINFO
  {
    public uint cbSize;    
    public uint dwTime;
  }

  public partial class Form1 : Form
  {

    [DllImport("User32.dll")]
    public static extern bool LockWorkStation();
    [DllImport("User32.dll")]
    private static extern bool GetLastInputInfo(ref LASTINPUTINFO Dummy);
    [DllImport("Kernel32.dll")]
    private static extern uint GetLastError();

public static uint GetIdleTime()
{
  LASTINPUTINFO LastUserAction = new LASTINPUTINFO();
  LastUserAction.cbSize = (uint)System.Runtime.InteropServices.Marshal.SizeOf(LastUserAction);
  GetLastInputInfo(ref LastUserAction);
  return ((uint)Environment.TickCount - LastUserAction.dwTime);
}

public static long GetTickCount()
{
  return Environment.TickCount;
}

public static long GetLastInputTime()
{
  LASTINPUTINFO LastUserAction = new LASTINPUTINFO();
  LastUserAction.cbSize = (uint)System.Runtime.InteropServices.Marshal.SizeOf(LastUserAction);
  if (!GetLastInputInfo(ref LastUserAction))
  {
    throw new Exception(GetLastError().ToString());
  }

  return LastUserAction.dwTime;
}

    public Form1()
    {
      InitializeComponent();
    }

    private void timer1_Tick(object sender, EventArgs e)
    {
      if (GetIdleTime() > 10000)  //10 secs, Time to wait before locking
        LockWorkStation();
    }

    private void Form1_Load(object sender, EventArgs e)
    {
      timer1.Start();
    }
  }
}



回答2:


IMO the accepted answer is not as good as this method:

http://www.codeproject.com/Articles/30345/Application-Idle

The CodeProject article uses Windows messages that will cause the component to consider the application not idle, eg

public enum ActivityMessages : int
{
    /// <summary>
    /// Cursor moved while within the nonclient area.
    /// </summary>
    WM_NCMOUSEMOVE = 0x00A0,
    /// <summary>
    /// Mouse left button pressed while the cursor was within the nonclient area.
    /// </summary>
    WM_NCLBUTTONDOWN = 0x00A1,
    /// <summary>
    /// Mouse left button released while the cursor was within the nonclient area.
    /// </summary>
    WM_NCLBUTTONUP = 0x00A2,
    /// <summary>



回答3:


Set a timeout on load, and every time an "active" action happens (you'll need to hook up to them), reset the timer back to the start.



来源:https://stackoverflow.com/questions/1541981/check-if-an-application-is-idle-for-a-time-period-and-lock-it

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