问题
I am doing topic modelling using the topicmodels package in R. I am creating a Corpus object, doing some basic preprocessing, and then creating a DocumentTermMatrix:
corpus <- Corpus(VectorSource(vec), readerControl=list(language="en"))
corpus <- tm_map(corpus, tolower)
corpus <- tm_map(corpus, removePunctuation)
corpus <- tm_map(corpus, removeWords, stopwords("english"))
corpus <- tm_map(corpus, stripWhitespace)
corpus <- tm_map(corpus, removeNumbers)
...snip removing several custom lists of stopwords...
corpus <- tm_map(corpus, stemDocument)
dtm <- DocumentTermMatrix(corpus, control=list(minDocFreq=2, minWordLength=2))
And then performing LDA:
LDA(dtm, 30)
This final call to LDA() returns the error
"Each row of the input matrix needs to contain at least one non-zero entry".
I assume this means that there is at least one document that has no terms in it after preprocessing. Is there an easy way to remove documents that contain no terms from a DocumentTermMatrix?
I looked in the documentation for the topicmodels package and found the function removeSparseTerms, which removes terms that do not appear in any document, but there is no analogue for removing documents.
回答1:
"Each row of the input matrix needs to contain at least one non-zero entry"
The error means that sparse matrix contain a row without entries(words). one Idea is to compute the sum of words by row
rowTotals <- apply(dtm , 1, sum) #Find the sum of words in each Document
dtm.new <- dtm[rowTotals> 0, ] #remove all docs without words
回答2:
agstudy's answer works great, but using it on a slow computer proved mildly problematic.
tic()
row_total = apply(dtm, 1, sum)
dtm.new = dtm[row_total>0,]
toc()
4.859 sec elapsed
(this was done with a 4000x15000 dtm)
The bottleneck appears to be applying sum() to a sparse matrix.
A document-term-matrix created by the tm package contains the names i and j , which are indices for where entries are in the sparse matrix. If dtm$i does not contain a particular row index p, then row p is empty.
tic()
ui = unique(dtm$i)
dtm.new = dtm[ui,]
toc()
0.121 sec elapsed
ui contains all the non-zero indices, and since dtm$i is already ordered, dtm.new will be in the same order as dtm. The performance gain may not matter for smaller document term matrices, but may become significant with larger matrices.
回答3:
This is just to elaborate on the answer given by agstudy.
Instead of removing the empty rows from the dtm matrix, we can identify the documents in our corpus that have zero length and remove the documents directly from the corpus, before performing a second dtm with only non empty documents.
This is useful to keep a 1:1 correspondence between the dtm and the corpus.
empty.rows <- dtm[rowTotals == 0, ]$dimnames[1][[1]]
corpus <- corpus[-as.numeric(empty.rows)]
回答4:
Just remove the sparse terms from the DTM and all will work well.
dtm <- DocumentTermMatrix(crude, sparse=TRUE)
回答5:
Just small addendum to the answer of Dario Lacan:
empty.rows <- dtm[rowTotals == 0, ]$dimnames[1][[1]]
will collect record's id, rather than order numbers. Try this:
library(tm)
data("crude")
dtm <- DocumentTermMatrix(crude)
dtm[1, ]$dimnames[1][[1]] # return "127", not "1"
If you construct your own corpus with consecutive numbering, after data cleaning some documents can be removed and numbering also will be broken. So, it's better to use id directly:
corpus <- tm_filter(
corpus,
FUN = function(doc) !is.element(meta(doc)$id, empty.rows))
# !( meta(doc)$id %in% emptyRows )
)
来源：https://stackoverflow.com/questions/13944252/remove-empty-documents-from-documenttermmatrix-in-r-topicmodels