问题
I am trying to learn more about Method chaining in Javascript and would like to know the proper way to create a delay with no jQuery to the next function in the chain:
var foo = function() {
this.delay = function(per) {
setTimeout(start, per);
return this;
};
this.start = function() {
alert('start!');
};
};
var bar = new foo().delay(1000).start();
回答1:
This isn't easy to do. jQuery uses a specific queue system.
Suppose you want to do it without jQuery, you would have to implement a queue yourself.
For example this very simplistic implementation :
var foo = function() {
var queue = [];
var timer;
this.delay = function(per) {
timer = setTimeout(function(){
timer = 0;
var f;
while (f = queue.shift()) f();
}, per);
return this;
};
this.addFunction = function(f) {
if (timer) queue.push(f);
else f();
return this;
};
this.start = function() {
this.addFunction(function(){alert('start')});
return this;
};
};
Demonstration
If you want to chain another function not defined in foo, you may do
var bar = new foo().delay(3000).start()
.addFunction(function(){alert("another chained one")});
Demonstration
回答2:
This will allow you to chain with multiple delays: http://jsfiddle.net/z4Uyf/1/
js:
var foo = function() {
var delayed = [];
var delayExecution = false;
var delayCount = 0;
function handleDelay(func){
delayed.push(func);
delayCount++;
}
function delayDone(){
delayExecution = false;
if( typeof(delayed[0]) == "function" ){
delayed[0]();
delayed.splice(0,1);
}
if( delayed.length > 0 ) delayExecution = true;
}
this.delay = function(per) {
delayExecution = true;
setTimeout(function(){
delayDone();
}, per);
return this;
};
this.start = function() {
if( delayExecution ){
handleDelay(arguments.callee);
}else{
alert("start!");
}
return this;
};
};
var bar = new foo().delay(1000).start().delay(5000).start();
来源:https://stackoverflow.com/questions/14365318/delay-to-next-function-in-method-chain