Open PIL image from byte file

我的未来我决定 提交于 2019-12-17 07:21:52

问题


I have this image with size 128 x 128 pixels and RGBA stored as byte values in my memory. But

from PIL import Image

image_data = ... # byte values of the image
image = Image.frombytes('RGBA', (128,128), image_data)
image.show()

throws the exception

ValueError: not enough image data

Why? What am I doing wrong?


回答1:


You can try this:

image = Image.frombytes('RGBA', (128,128), image_data, 'raw')
Source Code:
def frombytes(mode, size, data, decoder_name="raw", *args):
    param mode: The image mode.
    param size: The image size.
    param data: A byte buffer containing raw data for the given mode.
    param decoder_name: What decoder to use.



回答2:


The documentation for Image.open says that it can accept a file-like object, so you should be able to pass in a io.BytesIO object created from the bytes object containing the encoded image:

from PIL import Image
import io

image_data = ... # byte values of the image
image = Image.open(io.BytesIO(image_data))
image.show()


来源:https://stackoverflow.com/questions/32908639/open-pil-image-from-byte-file

标签
易学教程内所有资源均来自网络或用户发布的内容,如有违反法律规定的内容欢迎反馈
该文章没有解决你所遇到的问题?点击提问,说说你的问题,让更多的人一起探讨吧!