问题
I have encountered the following snippet:
pt->aa[!!(ts->flags & MASK)] = -val;
- What does
!!(double exclamation marks / exclamation points/ two not operators) stand for in c? - Isn't
(!!NULL) == NULL?
回答1:
! is negation. So !! is negation of negation. What is important is the fact that the result will be an int.
!!xifx == 0is!!0, that is!1, that is0.!!xifx != 0is!!(!0), that is!!1, that is!0, that is1.
!! is used commonly if you want to convert any non-zero value to 1 while being certain that 0 remains a 0.
And indeed, !!NULL == NULL, since !!NULL == !!0 and !!0 == !1 and finally !1 == 0.
Consequently, in the short piece of code you cited the array subscript will be either 0 if the value of the expression in parenthesis is NULL, and 1 otherwise.
回答2:
It is commonly (ab)used to convert any value into the ints 0 or 1 by repeated application of the boolean not operator, !.
For instance: !56 is 0, since 56 is "true" when viewed as a boolean. This means that !!56 is 1, since !0 is 1.
回答3:
!E is the same as E == 0 so !!E is the same as (E == 0) == 0. !! is used to normalize booleans values.
回答4:
In C99 you can replace it by
#include <stdbool.h>
pt->aa[(bool)(ts->flags & MASK)] = -val;
Of course if your code is to be portable to C89 then you'd be better off doing the !! trick or
pt->aa[(ts->flags & MASK)!=0] = -val;
or
pt->aa[(ts->flags & MASK)?1:0] = -val;
The generated code will be certainly identical.
回答5:
It converts a number into a canonical Boolean.
And note that in this case it's critical to do so, since the result is being used to index an array.
回答6:
!!xis just a!(!x).- if
NULLis defined as 0 then!!NULL == !!0 == !(!0) == !(1) == 0.
回答7:
!! is a decent way to quiet the compiler in certain situations such as assignment in a conditional with more than one expressions, e.g:
int _blah = 100;
int *blah;
if ( _blah > 100 && !!(blah = &_blah) ) {
// do stuff
}
I don't recommend this -- warnings are usually there to enforce good coding practice.
来源:https://stackoverflow.com/questions/14751973/what-is-in-c