Volatile Vs Atomic [duplicate]

问题

I read somewhere below line.

Java volatile keyword doesn't means atomic, its common misconception that after declaring volatile, ++ operation will be atomic, to make the operation atomic you still need to ensure exclusive access using synchronized method or block in Java.

So what will happen if two threads attack a volatile primitive variable at same time?

Does this mean that whosoever takes lock on it, that will be setting its value first. And if in meantime, some other thread comes up and read old value while first thread was changing its value, then doesn't new thread will read its old value?

What is the difference between Atomic and volatile keyword?

回答1:

The effect of the volatile keyword is approximately that each individual read or write operation on that variable is atomic.

Notably, however, an operation that requires more than one read/write -- such as i++, which is equivalent to i = i + 1, which does one read and one write -- is not atomic, since another thread may write to i between the read and the write.

The Atomic classes, like AtomicInteger and AtomicReference, provide a wider variety of operations atomically, specifically including increment for AtomicInteger.

回答2:

Volatile and Atomic are two different concepts. Volatile ensures, that a certain, expected (memory) state is true across different threads, while Atomics ensure that operation on variables are performed atomically.

Take the following example of two threads in Java:

Thread A:

value = 1;
done = true;

Thread B:

if (done)
  System.out.println(value);

Starting with value = 0 and done = false the rule of threading tells us, that it is undefined whether or not Thread B will print value. Furthermore value is undefined at that point as well! To explain this you need to know a bit about Java memory management (which can be complex), in short: Threads may create local copies of variables, and the JVM can reorder code to optimize it, therefore there is no guarantee that the above code is run in exactly that order. Setting done to true and then setting value to 1 could be a possible outcome of the JIT optimizations.

volatile only ensures, that at the moment of access of such a variable, the new value will be immediately visible to all other threads and the order of execution ensures, that the code is at the state you would expect it to be. So in case of the code above, defining done as volatile will ensure that whenever Thread B checks the variable, it is either false, or true, and if it is true, then value has been set to 1 as well.

As a side-effect of volatile, the value of such a variable is set thread-wide atomically (at a very minor cost of execution speed). This is however only important on 32-bit systems that i.E. use long (64-bit) variables (or similar), in most other cases setting/reading a variable is atomic anyways. But there is an important difference between an atomic access and an atomic operation. Volatile only ensures that the access is atomically, while Atomics ensure that the operation is atomically.

Take the following example:

i = i + 1;

No matter how you define i, a different Thread reading the value just when the above line is executed might get i, or i + 1, because the operation is not atomically. If the other thread sets i to a different value, in worst case i could be set back to whatever it was before by thread A, because it was just in the middle of calculating i + 1 based on the old value, and then set i again to that old value + 1. Explanation:

Assume i = 0
Thread A reads i, calculates i+1, which is 1
Thread B sets i to 1000 and returns
Thread A now sets i to the result of the operation, which is i = 1

Atomics like AtomicInteger ensure, that such operations happen atomically. So the above issue cannot happen, i would either be 1000 or 1001 once both threads are finished.

回答3:

There are two important concepts in multithreading environment.

atomicity
visibility

Volatile eradicates visibility problem but it does not deal with atomicity. Volatile will prevent compiler to reorder the instruction which involves write and subsequent read of a volatile variable. e.g. k++ Here k++ is not a single machine instruction rather it is three machine instructions.

copy the value to register
increment it
place it back

So even though you declare variable to volatile it will not make this operation atomic, which means another thread can see a intermediate result which is a stale or unwanted value for the other thread.

But AtomicInteger, AtomicReference are based on the Compare and swap instruction. CAS has three operands: a memory location V on which to operate, the expected old value A, and the new value B. CAS atomically updates V to the new value B, but only if the value in V matches the expected old value A; otherwise it does nothing. In either case, it returns the value currently in V. This is used by JVM in AtomicInteger, AtomicReference and they call the function as compareAndSet(). If this functionality is not supported by underlying processor then JVM implements it by spin lock.

回答4:

As Trying as indicated, volatile deals only with visibility.

Consider this snippet in a concurrent environment:

boolean isStopped = false;
    :
    :

    while (!isStopped) {
        // do some kind of work
    }

The idea here is that some thread could change the value of isStopped from false to true in order to indicate to the subsequent loop that it is time to stop looping.

Intuitively, there is no problem. Logically if another thread makes isStopped equal to true, then the loop must terminate. The reality is that the loop will likely never terminate even if another thread makes isStopped equal to true.

The reason for this is not intuitive, but consider that modern processors have multiple cores and that each core has multiple registers and multiple levels of cache memory that are not accessible to other processors. In other words, values that are cached in one processor's local memory are not visisble to threads executing on a different processor. Herein lies one of the central problems with concurrency: visibility.

The Java Memory Model makes no guarantees whatsoever about when changes that are made to a variable in on thread may become visible to other threads. In order to guarantee that updates are visisble as soon as they are made, you must synchronize.

The volatile keyword is a weak form of synchronization. While it does nothing for mutual exclusion or atomicity, it does provide a guarantee that changes made to a variable in one thread will become visible to other threads as soon as it is made. Because individual reads and writes to variables that are not 8-bytes are atomic in Java, declaring variables volatile provides an easy mechanism for providing visibility in situations where there are no other atomicity or mutual exclusion requirements.

回答5:

The volatile keyword is used:

to make non atomic 64-bit operations atomic: long and double. (all other, primitive accesses are already guaranteed to be atomic!)
to make variable updates guaranteed to be seen by other threads + visibility effects: after writing to a volatile variable, all the variables that where visible before writing that variable become visible to another thread after reading the same volatile variable (happen-before ordering).

The java.util.concurrent.atomic.* classes are, according to the java docs:

A small toolkit of classes that support lock-free thread-safe programming on single variables. In essence, the classes in this package extend the notion of volatile values, fields, and array elements to those that also provide an atomic conditional update operation of the form:

boolean compareAndSet(expectedValue, updateValue);

The atomic classes are built around the atomic compareAndSet(...) function that maps to an atomic CPU instruction. The atomic classes introduce the happen-before ordering as the volatile variables do. (with one exception: weakCompareAndSet(...)).

From the java docs:

When a thread sees an update to an atomic variable caused by a weakCompareAndSet, it does not necessarily see updates to any other variables that occurred before the weakCompareAndSet.

To your question:

Does this mean that whosoever takes lock on it, that will be setting its value first. And in if meantime, some other thread comes up and read old value while first thread was changing its value, then doesn't new thread will read its old value?

You don't lock anything, what you are describing is a typical race condition that will happen eventually if threads access shared data without proper synchronization. As already mentioned declaring a variable volatile in this case will only ensure that other threads will see the change of the variable (the value will not be cached in a register of some cache that is only seen by one thread).

What is the difference between AtomicInteger and volatile int?

AtomicInteger provides atomic operations on an int with proper synchronization (eg. incrementAndGet(), getAndAdd(...), ...), volatile int will just ensure the visibility of the int to other threads.

回答6:

So what will happen if two threads attack a volatile primitive variable at same time?

Usually each one can increment the value. However sometime, both will update the value at the same time and instead of incrementing by 2 total, both thread increment by 1 and only 1 is added.

Does this mean that whosoever takes lock on it, that will be setting its value first.

There is no lock. That is what synchronized is for.

And in if meantime, some other thread comes up and read old value while first thread was changing its value, then doesn't new thread will read its old value?

Yes,

What is the difference between Atomic and volatile keyword?

AtomicXxxx wraps a volatile so they are basically same, the difference is that it provides higher level operations such as CompareAndSwap which is used to implement increment.

AtomicXxxx also supports lazySet. This is like a volatile set, but doesn't stall the pipeline waiting for the write to complete. It can mean that if you read a value you just write you might see the old value, but you shouldn't be doing that anyway. The difference is that setting a volatile takes about 5 ns, bit lazySet takes about 0.5 ns.

来源：https://stackoverflow.com/questions/19744508/volatile-vs-atomic

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java

volatile