jQuery: Selecting all elements where attribute is greater than a value

问题

I know that to filter an element with an atttribute called attrName which has value attrValue I do:

filter("[attrName='attrValue']")

but looking at the docs http://api.jquery.com/category/selectors/ I can't see an option to select all elements s.t. attrName>attrValue

Will this work

   filter("[attrName>'attrValue']")

回答1:

You can do this using the function overload of .filter(), like this:

.filter(function() {
  return $(this).attr("attrName") > "someValue";
})

回答2:

The solution is jQuery.filter():

$("selector").filter(function() {
    return  $(this).attr("my-attr") > 123;
});

回答3:

Be careful, if you are playing with integers make sure you are using parseInt().

$("selector").filter(function() {
    return parseInt($(this).attr("my-attr")) > 123;
});

来源：https://stackoverflow.com/questions/2613648/jquery-selecting-all-elements-where-attribute-is-greater-than-a-value