问题
In Ruby, is it possible to pass by reference a parameter with value-type semantics (e.g. a Fixnum)? I'm looking for something similar to C#'s 'ref' keyword.
Example:
def func(x)
x += 1
end
a = 5
func(a) #this should be something like func(ref a)
puts a #should read '6'
Btw. I know I could just use:
a = func(a)
回答1:
You can accomplish this by explicitly passing in the current binding:
def func(x, bdg)
eval "#{x} += 1", bdg
end
a = 5
func(:a, binding)
puts a # => 6
回答2:
Ruby doesn't support "pass by reference" at all. Everything is an object and the references to those objects are always passed by value. Actually, in your example you are passing a copy of the reference to the Fixnum Object by value.
The problem with the your code is, that x += 1 doesn't modify the passed Fixnum Object but instead creates a completely new and independent object.
I think, Java programmers would call Fixnum objects immutable.
回答3:
In Ruby you can't pass parameters by reference. For your example, you would have to return the new value and assign it to the variable a or create a new class that contains the value and pass an instance of this class around. Example:
class Container
attr_accessor :value
def initialize value
@value = value
end
end
def func(x)
x.value += 1
end
a = Container.new(5)
func(a)
puts a.value
回答4:
You can try following trick:
def func(x)
x[0] += 1
end
a = [5]
func(a) #this should be something like func(ref a)
puts a[0] #should read '6'
回答5:
http://ruby-doc.org/core-2.1.5/Fixnum.html
Fixnum objects have immediate value. This means that when they are assigned or passed as parameters, the actual object is passed, rather than a reference to that object.
Also Ruby is pass by value.
回答6:
However, it seems that composite objects, like hashes, are passed by reference:
fp = {}
def changeit(par)
par[:abc] = 'cde'
end
changeit(fp)
p fp
gives
{:abc=>"cde"}
来源:https://stackoverflow.com/questions/161510/pass-parameter-by-reference-in-ruby