7-51 两个有序链表序列的合并 (20分)

泪湿孤枕 提交于 2019-12-17 03:19:00

7-51 两个有序链表序列的合并 (20分)

AC代码

#include <iostream>
#include <cstdio>
#include <vector>
#include <algorithm>
#include <cstdlib>
using namespace std;
typedef struct node{
    int data;
    struct node *nxt;
}node, *linklist;
linklist Read(){
    linklist L, op;
    L = (linklist)malloc(sizeof(node));
    L->data = -1;
    L->nxt = NULL;
    op = L;
    int data;
    scanf("%d", &data);
    while (data != -1){
        linklist tmp = (linklist)malloc(sizeof(node));
        tmp->nxt = NULL;
        tmp->data = data;
        op->nxt = tmp;
        op = op->nxt;
        scanf("%d", &data);
    }
    return L;
}
linklist Merge(linklist la, linklist lb){
    linklist L, pa, pb, op;
    L = (linklist)malloc(sizeof(node));
    L->data = -1;
    L->nxt = NULL;
    op = L;
    pa = la->nxt;
    pb = lb->nxt;
    while (pa != NULL && pb != NULL){
        if (pa->data <= pb->data){
            op->nxt = pa;
            pa = pa->nxt;
        }
        else {
            op->nxt = pb;
            pb = pb->nxt;
        }
        op = op->nxt;
    }
    while (pa != NULL){
        op->nxt = pa;
        pa = pa->nxt;
        op = op->nxt;
    }
    while (pb != NULL){
        op->nxt = pb;
        pb = pb->nxt;
        op = op->nxt;
    }
    op->nxt = NULL;
    return L;
}
int main(){
    linklist la, lb, lc;
    la = Read();
    lb = Read();
    lc = Merge(la, lb);
    linklist p = lc->nxt;
    if (p == NULL){
        printf("NULL");
        return 0;
    }
    int flag = 0;
    while (p != NULL){
        if (flag != 0) printf(" ");
        printf("%d", p->data);
        flag = 1;
        p = p->nxt;
    }
    return 0;
}
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