Get img src with PHP

问题

I would like to get the SRC attribute into a variable in this example:

<img border="0" src="/images/image.jpg" alt="Image" width="100" height="100" />

So for example - I would like to get a variable $foo = "/images/image.jpg". Important! The src attribute will be dynamic, so it mustn't be hardcoded. Is there any quick and easy way to do this?

Thanks!

EDIT: The image will be a part of a huge string that is basically the content of a news story. So the image is just a part of that.

EDIT2: There will be more images in this string, and I would only want to get the src of the first one. Is this possible?

回答1:

Use a HTML parser like DOMDocument and then evaluate the value you're looking for with DOMXpath:

$html = '<img id="12" border="0" src="/images/image.jpg"
         alt="Image" width="100" height="100" />';

$doc = new DOMDocument();
$doc->loadHTML($html);
$xpath = new DOMXPath($doc);
$src = $xpath->evaluate("string(//img/@src)"); # "/images/image.jpg"

Or for those who really need to save space:

$xpath = new DOMXPath(@DOMDocument::loadHTML($html));
$src = $xpath->evaluate("string(//img/@src)");

And for the one-liners out there:

$src = (string) reset(simplexml_import_dom(DOMDocument::loadHTML($html))->xpath("//img/@src"));

回答2:

You would be better off using a DOM parser for this kind of HTML parsing. Consider this code:

$html = '<img id="12" border="0" src="/images/image.jpg"
         alt="Image" width="100" height="100" />';
$doc = new DOMDocument();
libxml_use_internal_errors(true);
$doc->loadHTML($html); // loads your html
$xpath = new DOMXPath($doc);
$nodelist = $xpath->query("//img"); // find your image
$node = $nodelist->item(0); // gets the 1st image
$value = $node->attributes->getNamedItem('src')->nodeValue;
echo "src=$value\n"; // prints src of image

OUTPUT:

src=/images/image.jpg

回答3:

I have done that the more simple way, not as clean as it should be but it was a quick hack

$htmlContent = file_get_contents('pageURL');

// read all image tags into an array
preg_match_all('/<img[^>]+>/i',$htmlContent, $imgTags); 

for ($i = 0; $i < count($imgTags[0]); $i++) {
  // get the source string
  preg_match('/src="([^"]+)/i',$imgTags[0][$i], $imgage);

  // remove opening 'src=' tag, can`t get the regex right
  $origImageSrc[] = str_ireplace( 'src="', '',  $imgage[0]);
}
// will output all your img src's within the html string
print_r($origImageSrc);

回答4:

I know people say you shouldn't use regular expressions to parse HTML, but in this case I find it perfectly fine.

$string = '<img border="0" src="/images/image.jpg" alt="Image" width="100" height="100" />';
preg_match('/<img(.*)src(.*)=(.*)"(.*)"/U', $string, $result);
$foo = array_pop($result);

回答5:

$imgTag = <<< LOB
<img border="0" src="/images/image.jpg" alt="Image" width="100" height="100" />
<img border="0" src="/images/not_match_image.jpg" alt="Image" width="100" height="100" />
LOB;

preg_match('%<img.*?src=["\'](.*?)["\'].*?/>%i', $imgTag, $matches);
$imgSrc = $matches[1];

DEMO

---

NOTE: You should use an HTML Parser like DOMDocument and NOT a regex.

回答6:

$str = '<img border="0" src=\'/images/image.jpg\' alt="Image" width="100" height="100"/>';

preg_match('/(src=["\'](.*?)["\'])/', $str, $match);  //find src="X" or src='X'
$split = preg_split('/["\']/', $match[0]); // split by quotes

$src = $split[1]; // X between quotes

echo $src;

Other regexp's can be used to determine if the pulled src tag is a picture like so:

if(preg_match('/([jpg]{3}$)|([gif]{3}$)|([jpeg]{3}$)|([bmp]{3}$)|([png]{3}$)/', $src) == 1) {
//its an image
}

回答7:

There could be two easy solutions:

1. HTML it self is an xml so you can use any XML parsing method if u load the tag as XML and get its attribute tottally dynamically even dom data attribute (like data-time or anything).....
2. Use any html parser for php like http://mbe.ro/2009/06/21/php-html-to-array-working-one/ or php parse html to array Google this

来源：https://stackoverflow.com/questions/10130858/get-img-src-with-php