Gson handle object or array

问题

I've got the following classes

public class MyClass {
    private List<MyOtherClass> others;
}

public class MyOtherClass {
    private String name;
}

And I have JSON that may look like this

{
  others: {
    name: "val"
  }
}

or this

{
  others: [
    {
      name: "val"
    },
    {
      name: "val"
    }
  ]
}

I'd like to be able to use the same MyClass for both of these JSON formats. Is there a way to do this with Gson?

回答1:

I came up with an answer.

private static class MyOtherClassTypeAdapter implements JsonDeserializer<List<MyOtherClass>> {
    public List<MyOtherClass> deserialize(JsonElement json, Type typeOfT, JsonDeserializationContext ctx) {
        List<MyOtherClass> vals = new ArrayList<MyOtherClass>();
        if (json.isJsonArray()) {
            for (JsonElement e : json.getAsJsonArray()) {
                vals.add((MyOtherClass) ctx.deserialize(e, MyOtherClass.class));
            }
        } else if (json.isJsonObject()) {
            vals.add((MyOtherClass) ctx.deserialize(json, MyOtherClass.class));
        } else {
            throw new RuntimeException("Unexpected JSON type: " + json.getClass());
        }
        return vals;
    }
}

Instantiate a Gson object like this

Type myOtherClassListType = new TypeToken<List<MyOtherClass>>() {}.getType();

Gson gson = new GsonBuilder()
        .registerTypeAdapter(myOtherClassListType, new MyOtherClassTypeAdapter())
        .create();

That TypeToken is a com.google.gson.reflect.TypeToken.

You can read about the solution here:

https://sites.google.com/site/gson/gson-user-guide#TOC-Serializing-and-Deserializing-Gener

回答2:

Thank you three-cups for the solution!

The same thing with generic type in case it's needed for multiple types:

public class SingleElementToListDeserializer<T> implements JsonDeserializer<List<T>> {

private final Class<T> clazz;

public SingleElementToListDeserializer(Class<T> clazz) {
    this.clazz = clazz;
}

public List<T> deserialize(JsonElement json, Type typeOfT, JsonDeserializationContext context) throws JsonParseException {
    List<T> resultList = new ArrayList<>();
    if (json.isJsonArray()) {
        for (JsonElement e : json.getAsJsonArray()) {
            resultList.add(context.<T>deserialize(e, clazz));
        }
    } else if (json.isJsonObject()) {
        resultList.add(context.<T>deserialize(json, clazz));
    } else {
        throw new RuntimeException("Unexpected JSON type: " + json.getClass());
    }
    return resultList;
    }
}

And configuring Gson:

Type myOtherClassListType = new TypeToken<List<MyOtherClass>>() {}.getType();
SingleElementToListDeserializer<MyOtherClass> adapter = new SingleElementToListDeserializer<>(MyOtherClass.class);
Gson gson = new GsonBuilder()
    .registerTypeAdapter(myOtherClassListType, adapter)
    .create();

回答3:

Building off three-cups answer, I have the following which lets the JsonArray be deserialized directly as an array.

static public <T> T[] fromJsonAsArray(Gson gson, JsonElement json, Class<T> tClass, Class<T[]> tArrClass)
        throws JsonParseException {

    T[] arr;

    if(json.isJsonObject()){
        //noinspection unchecked
        arr = (T[]) Array.newInstance(tClass, 1);
        arr[0] = gson.fromJson(json, tClass);
    }else if(json.isJsonArray()){
        arr = gson.fromJson(json, tArrClass);
    }else{
        throw new RuntimeException("Unexpected JSON type: " + json.getClass());
    }

    return arr;
}

Usage:

    String response = ".......";

    JsonParser p = new JsonParser();
    JsonElement json = p.parse(response);
    Gson gson = new Gson();
    MyQuote[] quotes = GsonUtils.fromJsonAsArray(gson, json, MyQuote.class, MyQuote[].class);

来源：https://stackoverflow.com/questions/7668507/gson-handle-object-or-array