问题
I'm looking to compare two varchars in SQL, one would be something like Cafe and the other Café is there a way in SQL that will allow the two values to be compared. For instance:
SELECT *
FROM Venue
WHERE Name Like '%cafe%'
So if there is a venue with the name Big Bobs Café Extraordinaire it would be included in the result set?
回答1:
Coerce to an accent insensitive collation
You'll also need to ensure both side have the same collation to avoid errors or further coercions if you want to compare against a table variable or temp table varchar column
and because the constant value will have the collation of the database Update: only for local variables, not for constants nope, not even then
SELECT *
FROM Venue
WHERE
Name COLLATE Latin1_general_CI_AI Like '%cafe%' COLLATE Latin1_general_CI_AI
回答2:
By applying a specific accent insensitive collation to your select:
SELECT *
FROM Venue
WHERE Name COLLATE Latin1_General_CI_AI Like '%cafe%' COLLATE Latin1_General_CI_AI
The CI stands for "Case Insensitive" and AI for "Accent Insensitive".
回答3:
Accent Sensitive and Accent Insensitive searching can be don by using Latin1_general_CI_AI
Here AI is for Accent Insensitive and AS for Accent Sensitive
ie, Café and Cafe are the same if Accent Insensitive.
In the below query Latin1_general_CI_AI can be break down into the following parts.
latin1makes the server treat strings using charset latin 1, basically ascii.CI specifies case-insensitive, so "ABC" equals to "abc".
- AI specifies accent-insensitive,so 'ü' equals to 'u'.
Your query should be as follows:
SELECT * FROM Venue WHERE Name COLLATE Latin1_general_CI_AI Like '%cafe%' COLLATE Latin1_general_CI_AI
Expected Result is as follows:
Id name
1 Café
2 Cafe
回答4:
if 'A' COLLATE SQL_Latin1_General_CP1_CS_AS= 'a' COLLATE SQL_Latin1_General_CP1_CS_AS SELECT N'Yes' ELSE SELECT N'No'
来源：https://stackoverflow.com/questions/2461522/how-do-i-perform-an-accent-insensitive-compare-e-with-%c3%a8-%c3%a9-%c3%aa-and-%c3%ab-in-sql-ser