问题
I need to make sure that a certain long value isn't in an array. But for some reason, this isn't working...
!d.toString().contains(sq.toString());
I am sure I am getting something really backwards... but I can't figure out what!
回答1:
Try
!Arrays.asList(d).contains(sq);
回答2:
Look at the static methods in java.util.Arrays. Your array will need to be sorted for the binarySearch() to work.
来源:https://stackoverflow.com/questions/5010044/checking-if-long-is-in-array