Ignoring the first line of stderr and keeping stdout intact

问题

mongodump prints a single debug message to stderr every time it is run, which is causing some unintended side effects. How do I ignore only the first line of stderr and keep everything else intact?

I'm piping stdout to a file, so I can't combine stderr and stdout.

回答1:

Using a process substitution, and piping stdout into rev to see that stderr is unaffected

{  echo stderr1 >&2; echo stdout1; echo stderr2 >&2; } 2> >(sed 1d >&2) | rev

1tuodts
stderr2

来源：https://stackoverflow.com/questions/19759660/ignoring-the-first-line-of-stderr-and-keeping-stdout-intact