问题
I've written a unit test for a function that calls the jQuery getJSON
method. The only thing that I'm testing is that it is called with the expected URL. My unit test uses a Jasmine Spy to mock the API call. However, when I run my unit tests I get this error:
1) should make a request to the expected URL when running on localhost
test module getDataFromApi function
TypeError: Cannot read property 'fail' of undefined
In my unit test I've created a Jasmine Spy, which returns the done
and fail
methods. What am I doing wrong here?
Here is my unit test:
describe('getFundDataFromApi function', function () {
beforeEach(function () {
spyOn($, "getJSON").and.callFake(function () {
return {
done: function () {},
fail: function () {}
};
});
});
it('should make a request to the expected URL when running on localhost', function () {
var expectedUrl = '/assets/mock-data/mock-data.json';
module.getDataFromApi();
expect($.getJSON).toHaveBeenCalled();
expect($.getJSON).toHaveBeenCalledWith({url:expectedUrl});
});
});
Function I'm trying to test: getDataFromApi
getDataFromApi: function () {
var mod = this;
var url = this.settings.apiUrl;
$.getJSON({
url: url
})
.done(function (data) {
mod.processApiData(data);
})
.fail(function () {
mod.displayErrorMessage();
});
},
回答1:
In your function getDataFromApi
you are chaining the call of fail
after done
but, in the mocked version of done
, it returns nothing(undefined
), so, you get TypeError: Cannot read property 'fail' of undefined.
You can make the done
function to return an object with a fail
property that is a function.
beforeEach(function() {
spyOn($, "getJSON").and.callFake(function() {
return {
done: function() {
return { fail: function() {} };
}
};
});
});
Or, one line ES6 versionspyOn($, "getJSON").and.callFake(() => ({ done: () => ({fail: () => {}}) }));
Or, if you are planning to do more in your tests, like testing success or failed responses, probably returning a jQuery Deferred can help you
beforeEach(function() {
spyOn($, "getJSON").and.callFake(function() {
const deferred = $.Deferred();
deferred.resolve({'success': true});
return deferred;
});
});
Calling deferred.reject({'success': false});
will give you the chance to test for errors.
Hope it helps
来源:https://stackoverflow.com/questions/53392072/unit-testing-jquery-getjson-function-errors-with-the-fail-method-using-jasmine