Why does matplotlib's Slider only allow a range of 0-7?

问题

I am trying to plot the values of a bitwise circular shift on 1 byte. I'd like to have a slider let me change the original input value. I'm using the slider example on the matplotlib site for reference, but for some reason even though I pass in 0-255 as my slider range when I run my script the range is always 0-7. I'm guessing that somehow the slider is getting locked to my maximum number of x values, but I don't see how. How do I get the slider to let me pick the full 0-255 range?

Also, despite the min/max I've given the slider it inserts some padding for going below 0 at the front, and randomly draws a verticle line in the middle of my slider. How do I get rid of it? (also what is it for? The purpose isn't obvious to me)

Picture of slider only going up to 7:

Code:

import matplotlib.pyplot as plt
from matplotlib.widgets import Slider

from numpy import uint8
from numpy import uint16
from numpy import uint32
from numpy import uint64

def sizeof(x):
    return [uint8, uint16, uint32, uint64].index(x) + 1

def rot(x, i):
    return type(x)((x >> i) | (x << (sizeof(type(x))*8 - i))) 

def plotShifts(x):
    origType = type(x)
    maxval = type(x)(-1)

    numrots = sizeof(type(x)) * 8
    vals = [rot(x, i) for i in range(numrots)]

    print vals

    l, = plt.plot(range(numrots), vals, 'ro')

    axcolor = 'lightgoldenrodyellow'
    inputax = plt.axes([0.15, 0.05, 0.65, 0.03], axisbg=axcolor)
    inputsl = Slider(inputax, 'Input', 0, maxval, valinit=0, valfmt="%d")

    def update(x):
        vals = [rot(origType(x), i) for i in range(numrots)]
        l.set_ydata(vals)
        plt.draw()
    inputsl.on_changed(update)

    plt.axis([-0.5, numrots-1 + 0.5, -2, maxval + 2])

plotShifts(uint8(1))
plt.show()

回答1:

The problem is in the last line plt.axis([-0.5, numrots-1 + 0.5, -2, maxval + 2]) which is acting on the axes that holds the slider, not on the axis with the data.

I would recommend using the OO interface to matplotlib rather than the pyplot interface for anything programmatic. The pyplot interface is good for interactive stuff, but it has a good deal of hidden state.

You also need to return a reference to the slider object due to the way call backs work.

import matplotlib.pyplot as plt
from matplotlib.widgets import Slider

from numpy import uint8
from numpy import uint16
from numpy import uint32
from numpy import uint64

def sizeof(x):
    return 2 ** [uint8, uint16, uint32, uint64].index(x)

def rot(x, i):
    return type(x)((x >> i) | (x << (sizeof(type(x))*8 - i))) 

def plotShifts(x):
    fig = plt.figure() # make a new figure
    ax = fig.add_axes([0.15, 0.2, 0.65, 0.7]) # add data axes
    origType = type(x)
    maxval = type(x)(-1)

    numrots = sizeof(type(x)) * 8
    vals = [rot(x, type(x)(i)) for i in range(numrots)]

    print vals
    print maxval
    l, = ax.plot(range(numrots), vals, 'ro') # plot to data axes

    axcolor = 'lightgoldenrodyellow'
    inputax = fig.add_axes([0.15, 0.05, 0.65, 0.03], axisbg=axcolor)
    inputsl = Slider(inputax, 'Input', 0, maxval, valinit=0, valfmt="%d")

    def update(x):
        vals = [rot(origType(x), origType(i)) for i in range(numrots)]
        l.set_ydata(vals)
        plt.draw()
    inputsl.on_changed(update)

    ax.set_ylim([-2,maxval +2]) # set ylim on data axes
    ax.set_xlim([-.5,numrots-1+.05]) # set xlim on data axes


    return inputsl

sldr = plotShifts(uint8(1))
plt.show()

回答2:

most likely because maxval =7 in this line

inputsl = Slider(inputax, 'Input', 0, maxval, valinit=0, valfmt="%d")

来源：https://stackoverflow.com/questions/12980919/why-does-matplotlibs-slider-only-allow-a-range-of-0-7