问题
I can't find a way to convert my QList<T> to a QVariant.
There's a constructor QVariant(const QList<QVariant> &val), but no constructor for QList<T> , is it possible to convert directly a QList<T> ?
回答1:
Example
QList<int> ints{1,2,3};
QVariant var = QVariant::fromValue<QList<int>>(ints);
来源:https://stackoverflow.com/questions/44436386/how-to-convert-qlistt-to-qvariant