问题
i have the following code to for xml serialization.
public class FormSaving
{
private string major;
public string Majorversion
{
get;
set;
}
}
private void SaveButton_Click(object sender, RoutedEventArgs e)
{
string savepath;
SaveFileDialog DialogSave = new SaveFileDialog();
// Default file extension
DialogSave.DefaultExt = "txt";
// Available file extensions
DialogSave.Filter = "XML file (*.xml)|*.xml|All files (*.*)|*.*";
// Adds a extension if the user does not
DialogSave.AddExtension = true;
// Restores the selected directory, next time
DialogSave.RestoreDirectory = true;
// Dialog title
DialogSave.Title = "Where do you want to save the file?";
// Startup directory
DialogSave.InitialDirectory = @"C:/";
DialogSave.ShowDialog();
savepath = DialogSave.FileName;
DialogSave.Dispose();
DialogSave = null;
FormSaving abc = new FormSaving();
abc.Majorversion = MajorversionresultLabel.Content.ToString();
using (Stream savestream = new FileStream(savepath, FileMode.Create))
{
XmlSerializer serializer = new XmlSerializer(typeof(FormSaving));
serializer.Serialize(savestream, abc);
}
}
private void LoadButton_Click(object sender, RoutedEventArgs e)
{
Stream checkStream = null;
Microsoft.Win32.OpenFileDialog DialogLoad = new Microsoft.Win32.OpenFileDialog();
DialogLoad.Multiselect = false;
DialogLoad.Filter = "XML file (*.xml)|*.xml|All files (*.*)|*.*";
if ((bool)DialogLoad.ShowDialog())
{
try
{
if ((checkStream = DialogLoad.OpenFile()) != null)
{
loadpath = DialogLoad.FileName;
checkStream.Close();
}
}
catch (Exception ex)
{
System.Windows.MessageBox.Show("Error: Could not read file from disk. Original error: " + ex.Message);
}
}
else
{
System.Windows.MessageBox.Show("Problem occured, try again later");
}
FormSaving abc;
using (Stream loadstream = new FileStream(loadpath, FileMode.Create))
{
XmlSerializer serializer = new XmlSerializer(typeof(FormSaving));
abc = (FormSaving)serializer.Deserialize(loadstream);
}
MajorversionresultLabel.Content = abc.Majorversion;
}
When i press the SaveButton, my label.content is saved into an xml file. However when i press the load button to load this xml file, i get the error "There is an error in XML document (0, 0)". I went to open my xml file after pressing the load button, it becomes blank and everything got erased. Can anyone help me fix this load button error?
回答1:
ok solved,
using (Stream loadstream = new FileStream(loadpath, FileMode.Open))
{
XmlSerializer serializer = new XmlSerializer(typeof(FormSaving));
abc = (FormSaving)serializer.Deserialize(loadstream);
}
should have been FileMode.Open instead of FileMode.Create
来源:https://stackoverflow.com/questions/5099476/there-is-an-error-in-xml-document-0-0-during-deserialization