GLSL error: `out' qualifier only valid for function parameters in GLSL 1.10 [closed]

问题

Closed. This question is off-topic. It is not currently accepting answers.

---

Want to improve this question? Update the question so it's on-topic for Stack Overflow.

Closed 3 years ago.

My shaders have in/out keywords. But I've got GLSL compile error: 'out' qualifier only valid for function parameters in GLSL 1.10. Shaders have #version 330 directive. Calling glGetString(GL_SHADING_LANGUAGE_VERSION) returns 3.30.

Here is my project: github.com/wlad031/ssu-coursework-2016. Input folder contains shaders. Main source files are src/ShaderProgramControl.cpp and src/Shader.cpp. Where is my mistake?

回答1:

In your src/FileReader.cpp you have :

        if (first != '#') {
            res.push_back(line);
        }

And this strips out the #version 330 ...

来源：https://stackoverflow.com/questions/37590152/glsl-error-out-qualifier-only-valid-for-function-parameters-in-glsl-1-10