php dynamically generate new web page from link [closed]

问题

i need serious help here! i have this site am building: a summary of each article is generated from the database with the title as a link, but i want it to be that if someone clicks on the link, a page of the article is automatically generated without hustling; for i cannot code a page for every article i have in the database! here's my code that generates a summary:

<?php
        if(isset($_POST['search'])){
                $term = mysql_real_escape_string($_POST['keyword']);

                        $search = mysql_query("select * from article 
                        where match(title, body) against('$term') ");

                    if(mysql_num_rows($search)>0){  

                            echo "<div>"."Search Results For: "."<h3><u>".$term."</u></h3>"."</div>";

                            while($result = mysql_fetch_array($search)){

                                    echo "<div class=\"article\">".

                                    "<div class=\"title\"><a href=\"".$result['cat'].".php"."\">".$result['title']."</a></div>".
                                    "<div class=\"body\">".substr($result['body'], 0, 250)."</div>".
                                    "<div class=\"cat\"><a href=\"".$result['cat'].".php"."\">"."Category: ".$result['cat']."</a></div>".
                                    "<div class=\"author\">"."Author: ".$result['author']."</div>".
                                    "<div class=\"dateTime\">"."Date: ".$result['date']."</div>".

                                        "</div>";
                                }

                    }   


                    else{
                            echo "Sorry! The search for "."<h3>".$term."</h3>"." gave no results.";
                        }

                }

    ?>

回答1:

Assuming each of the articles has its ID. Change the link to go to a dynamic page, passing that ID:

"<div class=\"title\"><a href=\"dynamic_page.php?id=$result[id]\">$result[title]</a></div>"

Then create a dynamic_page.php that accepts that ID and generates the article as follows:

if (isset($_GET['id'])) {
    $id = mysql_real_escape_string($_GET['id']);
    $q = "SELECT
            *
        FROM
            `article`
        WHERE
            `id` = '$id'
        LIMIT 1;";
    $q = mysql_query($q);
    if (mysql_num_rows($q) > 0) {
        $result = mysql_fetch_assoc($q);
        echo "<div class=\"article\">".
                "<div class=\"title\">".$result['title']."</div>".
                "<div class=\"body\">".$result['body']."</div>".
                "<div class=\"cat\"><a href=\"".$result['cat'].".php"."\">"."Category: ".$result['cat']."</a></div>".
                "<div class=\"author\">"."Author: ".$result['author']."</div>".
                "<div class=\"dateTime\">"."Date: ".$result['date']."</div>".
            "</div>";
    }
    else {
        /* Article not found */
    }
}

Note that the $result['body'] is shown in full this time. Also I suggest using mysql_fetch_assoc() in your case.

The code is here

回答2:

If the link is something like page.com/article.php?id=20 then your query would look like the following:

$id = mysql_real_escape_string($_GET['id']);
mysql_query("SELECT * FROM articles WHERE id = '$id'");

Then you can use mysql_fetch_array to display the data.

来源：https://stackoverflow.com/questions/13749042/php-dynamically-generate-new-web-page-from-link

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php

mysql

dynamic