问题
I am using phone number texfield, now i am using this format for texfield (#) #### #####, now issue is that i want first character 0 as compulsary, like this (0) 1234 56789, so user enter whatever first character must be typed 0, its not duplicate quesion number format is different
here is my code but its not working
func textField(_ textField: UITextField, shouldChangeCharactersIn range: NSRange, replacementString string: String) -> Bool {
var oldText = (textField.text! as NSString).replacingCharacters(in: range, with: string)
if oldText.count > 15 { return false }
oldText = oldText.replacingOccurrences(of: "(0)", with: "").replacingOccurrences(of: " ", with: "")
if !oldText.isEmpty {
oldText = "(0)" + oldText
}
let newText = String(stride(from: 0, to: oldText.count, by: 3).map {
let sIndex = String.Index(encodedOffset: $0)
let eIndex = oldText.index(sIndex, offsetBy: 3, limitedBy: oldText.endIndex) ?? oldText.endIndex
return String(oldText[sIndex..<eIndex])
}.joined(separator: " "))
textField.text = newText
return false
}
回答1:
In this format (#) #### ##### only two spaces are used. So you can insert space at a particular index without a for loop like this
func textField(_ textField: UITextField, shouldChangeCharactersIn range: NSRange, replacementString string: String) -> Bool {
var oldText = (textField.text! as NSString).replacingCharacters(in: range, with: string)
if oldText.count > 14 { return false }
oldText = oldText.replacingOccurrences(of: "(0)", with: "").replacingOccurrences(of: " ", with: "")
if !oldText.isEmpty {
oldText = "(0)" + oldText
}
if oldText.count > 3 {
oldText.insert(" ", at: oldText.index(oldText.startIndex, offsetBy: 3))
}
if oldText.count > 8 {
oldText.insert(" ", at: oldText.index(oldText.startIndex, offsetBy: 8))
}
textField.text = oldText
return false
}
来源：https://stackoverflow.com/questions/56360558/uitextfiled-with-first-letter-must-0-and-format-will-be-like-0-1234-56789