问题
I have a simple C++ code where I define a dynamic array as:
std::vector<double>IPWeights;
and then pass it to a function called reference with a reference (so I changed its content) like:
void reference (std::vector<double> &IPWeights)
and then in my main function, after I changed my arrays content I wanted to print it like:
int size_weights=IPWeights.size();
for (int i=0; i<size_weights; i++)
{
std::cout<<IPWeights[i]<<std::endl;
}
but in the screen I only see "segmentation fault 11".
where the reference is simply looks like:
void reference( std::vector<double> &IPWeights)
{
IPWeights[0]=0.4500;
IPWeights[1]=0.2648;
IPWeights[2]=0.2648;
IPWeights[3]=0.2648;
IPWeights[4]=0.2519;
IPWeights[5]=0.2519;
IPWeights[6]=0.2519;
}
Any advice is appreciated, Thanks in advance.
回答1:
My crystal ball says that you don't allocate memory for the vector. You should do one of the following:
Initialize vector with appropriate size:
std::vector<double> IPWeights(size_you_need);Call
IPWeights.resize()before assigning to it:std::vector<double> IPWeights; IPWeights.resize(size_you_need);Call
IPWeights.push_back()instead of assigning by index:IPWeights.push_back(0.4500); IPWeights.push_back(0.2648); //...
来源:https://stackoverflow.com/questions/27400767/segmentation-fault-11-while-printing-dynamic-arrays