问题
A couple of questions really about the code below from which I gained assistance in a previous post.
1). Any ideas why at the end of the ouput, I get a random garbage character printed? I am freeing the files etc and checking for EOF.
2). The idea is that it can work with multiple file arguements, so I want to create new file names which increment, i.e. out[i].txt, is that possible in C?
The code itself takes a file containing words all separated by spaces, like a book for example, then loops through, and replaces each space with a \n so that it forms a list, please find the code below:
#include <stdlib.h>
#include <ctype.h>
#include <string.h>
#include <stdio.h>
/*
*
*/
int main(int argc, char** argv) {
FILE *fpIn, *fpOut;
int i;
char c;
while(argc--) {
for(i = 1; i <= argc; i++) {
fpIn = fopen(argv[i], "rb");
fpOut= fopen("tmp.out", "wb");
while (c != EOF) {
c = fgetc(fpIn);
if (isspace(c))
c = '\n';
fputc(c, fpOut );
}
}
}
fclose(fpIn);
fclose(fpOut);
return 0;
}
回答1:
When you reach the end of file, you don't break the loop. So you are calling fputc(c, fpOut); with c==EOF which is probably an undefined behavior, or at least the writing of a \0xff byte.
And you don't call fclose inside your while(argc--) loop, so your files (except the last) are mostly never closed nor flushed.
At last, you don't test the result of fopen and you should test that it is non null (and print an error message, perhaps with something about strerror(errno) or perror, in that case).
You should have found out with a debugger (like gdb on Linux), and perhaps with the help of compiler warnings (but gcc-4.6 -Wall did not caught any bugs on your example).
You could decide that the output file name is related to input file name, perhaps with
char outname[512];
for(i = 1; i < argc; i++) {
fpIn = fopen(argv[i], "rb");
if (!fpIn) { perror (argv[i]); exit(1); };
memset (outname, 0, sizeof (outname));
snprintf (outname, sizeof(outname)-1, "%s~%d.out", argv[i], i);
fpOut= fopen(outname, "wb");
if (!fpOut) { perror (outname); exit(1); };
/// etc...
fclose(fpIn);
fclose(fpOut);
fpIn = fpOut = NULL;
}
回答2:
Suggested changes (all untested):
#include <stdlib.h>
#include <ctype.h>
#include <string.h>
#include <stdio.h>
int
main(int argc, char** argv) {
FILE *fpIn, *fpOut;
int i;
char c;
for(i = 1; i < argc; i++) {
fpIn = fopen(argv[i], "rb");
if (!fpIn) {
perror ("Unable to open input file");
continue;
}
fpOut= fopen("tmp.out", "wb");
if (!fpOut) {
perror ("Unable to open output file");
fclose (fpIn);
continue;
}
while ((c = fgetc (fpIn)) != EOF)) {
if (isspace(c))
c = '\n';
fputc(c, fpOut );
}
fclose(fpIn);
fclose(fpOut);
}
return 0;
}
来源:https://stackoverflow.com/questions/8649068/working-with-text-files-two