Create user-friendly date in PHP

问题

System returns me that date 20110408.

Is it possible to covert it to 8 April 2011? I'm using PHP5. Can't figure out how to do that with DateTime class.

回答1:

date function <--

$original_date = '20110408';
date('d F Y', strtotime($original_date));

回答2:

try these

echo date("Y-m-d H:i:s")."<br />";
echo date("F j, Y")."<br />";
echo date("j F Y")."<br />";

回答3:

You can use:

date("j F Y", strtotime('20110408'));

回答4:

You could always use:

function formatDate($date) {
    // 20110408 -> 8 April 2011
    $months = array('January', 'February', 'March', 'April', 'May', 'June', 'July', 'August', 'September', 'October', 'November', 'December');
    $year = substr($date, 0, 4);
    $month = $months[intval(substr($date, 4, 2))-1];
    $day = (int)substr($date, -2);
    return sprintf("%d %s %d", $day, $month, $year);
}

I hope that's not too easy!

来源：https://stackoverflow.com/questions/5919387/create-user-friendly-date-in-php