@Formula field is not recognized by client code

问题

Related to: How to countDistinct on multiple columns

I have an entity class that contains many fields, three of which are longitude, latitude and update_time. I am trying to add a @Formula field that concatenates the three:

@Formula("concat(longitude, latitude, update_time)")
public String fix;

I would then like to use that field as part of a countDistinct query:

@SuppressWarnings( {"unchecked", "rawtypes"} )
public long getCountDistinctPositions() {
    Session session = sessionFactory.openSession();

    CriteriaBuilder criteriaBuilder = session.getCriteriaBuilder();

    CriteriaQuery criteriaQuery = criteriaBuilder.createQuery();
    Root<Position> position = criteriaQuery.from(Position.class);
    Expression fix = position.get("fix");
    Expression countDistinct = criteriaBuilder.countDistinct(fix);
    criteriaQuery.select(countDistinct);
    Query query = session.createQuery(criteriaQuery);
    Long result = (Long)query.getSingleResult();

    session.close();

    return result;
}

But I keep getting an exception:

java.lang.IllegalArgumentException: Unable to locate Attribute  with the the given name [fix] on this ManagedType [aaa.Position]

回答1:

A @Formula field cannot be queried, its basically a synthetic field that Hibernate will populate when a select query is executed only.

For your use case, you'd need to execute:

SELECT DISTINCT longitude, latitude, update_time FROM Entity

From a JPA query perspective, you'd need to execute #countDistinct on all 3 individual columns, not on the formula-column.

The best way to think of a formula column is that you've effectively translated the following method on your entity

@Transient
public String getFix() {
  return this.longitude + this.latitude + this.update_time;
}

to a property that the database concatenates for you at query-time.

UPDATE

CriteriaQuery<Long> countQuery = cb.createQuery( Long.class );
Root<TheEntity> root = countQuery.from( TheEntity.class );

countQuery.select( cb.count( root.get( "id" ) ) );

Subquery<Integer> subQuery = countQuery.subquery( Integer.class );
Root<TheEntity> subRoot = subQuery.from( TheEntity.class );
subQuery.select( cb.min( subRoot.get( "id" ) ) );
subQuery.groupBy( subRoot.get( "longitude" ), 
   subRoot.get( "latitude" ), 
   subRoot.get( "updateTime" ) );

countQuery.where( root.get( "id" ).in( subQuery ) );

Long count = entityManager.createQuery( countQuery ).getSingleResult();

来源：https://stackoverflow.com/questions/50411647/formula-field-is-not-recognized-by-client-code

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hibernate

jpa

aggregate