问题
I am currently trying to flatten a large recurisve XML document, so that all the nested elements stay on root level but get an additional new attribute ("parent_id=...") to still keep the relations between the nodes.
Each node has a lot of sub-nodes which i also need to grab, so the content has to stay the same.
The file is very large (500k Rows - 33 MB in Size)
Example XML:
<product-catalog ...>
<category id="1">
<content>
...
</content>
<category id="2">
<content>
...
</content>
</category>
<category id="3">
<content>
...
</content>
<category id="4">
...
</category>
<category id="5">
...
</category>
</category>
</category>
</product-catalog>
Required flattened output:
<product-catalog>
<category id="1" parent_id="0">
<content>...</content>
</category>
<category id="2" parent_id="1">
<content>...</content>
</category>
<category id="3" parent_id="1">
<content>...</content>
</category>
<category id="4" parent_id="3">
<content>...</content>
</category>
<category id="5" parent_id="3">
<content>...</content>
</category>
</product-catalog>
tried this so far, but it only delivers root category (not really an xslt-expert... ;))
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="@* | node()">
<xsl:copy>
<xsl:apply-templates select="@* | node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="category">
<xsl:element name="category">
<xsl:apply-templates select="@* | node() [not(child::category)]"/>
</xsl:element>
</xsl:template>
<!-- remove -->
<xsl:template match="translations" />
</xsl:stylesheet>
回答1:
Consider the following example:
XML
<product-catalog>
<category id="1">
<content>A1</content>
<category id="2">
<content>B</content>
</category>
<category id="3">
<content>C1</content>
<content>C2</content>
<category id="4">
<content>D</content>
</category>
<category id="5">
<content>E</content>
</category>
</category>
<content>A2</content>
</category>
</product-catalog>
XSLT 1.0
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="/product-catalog">
<xsl:copy>
<xsl:apply-templates select="category"/>
</xsl:copy>
</xsl:template>
<xsl:template match="category">
<category id="{@id}" parent_id="{parent::category/@id}">
<xsl:copy-of select="content"/>
</category>
<xsl:apply-templates select="category"/>
</xsl:template>
</xsl:stylesheet>
Result
<?xml version="1.0" encoding="UTF-8"?>
<product-catalog>
<category id="1" parent_id="">
<content>A1</content>
<content>A2</content>
</category>
<category id="2" parent_id="1">
<content>B</content>
</category>
<category id="3" parent_id="1">
<content>C1</content>
<content>C2</content>
</category>
<category id="4" parent_id="3">
<content>D</content>
</category>
<category id="5" parent_id="3">
<content>E</content>
</category>
</product-catalog>
how could i copy all existing attributes of
<category...>
and add only parent_id
Try:
<xsl:template match="category">
<category parent_id="{parent::category/@id}">
<xsl:copy-of select="@* | content"/>
</category>
<xsl:apply-templates select="category"/>
</xsl:template>
来源:https://stackoverflow.com/questions/57445013/how-to-flatten-a-very-complex-xml-into-a-new-xml-containing-all-nodes-at-root-le