Creating an array variable with a variable number of elements

问题

I want to define an array variable to have a variable number of elements depending on the m number of results returned from a search. I get an error "Constant Expression Required" on:

Dim cmodels(0 To m) As String

Here is my complete code

Dim foundRange As Range
Dim rangeToSearch As Range
Set rangeToSearch = Selection
Set foundRange = rangeToSearch.Find(What:="Lights", After:=ActiveCell,            
LookIn:=xlValues, LookAt:= _
xlPart, SearchOrder:=xlByRows, SearchDirection:=xlNext, MatchCase:=False _
, SearchFormat:=False) 'First Occurrence
    m = WorksheetFunction.CountIf(Selection, "Lights")
 Dim secondAddress As String
If (Not foundRange Is Nothing) Then
    Dim count As Integer: count = 0
    Dim targetOccurrence As Integer: targetOccurrence = 2
    Dim found As Boolean
    z = 1
    Dim cmodels(0 To m) As String
    Do Until z = m
    z = z + 1
        foundRange.Activate
        Set foundRange = rangeToSearch.FindNext(foundRange)
        If Not foundRange.Next Is Nothing Then
        z(m) = ActiveCell(Offset(0, 2))
        End If
    Loop
    End If
End Sub

回答1:

See the following code comments:

Sub redimVsRedimPreserve()

    'I generally declare arrays I know I will resize
    'without a fixed size initially..
    Dim cmodels() As String
    Dim m As Integer
    m = 3

    'this will wipe out all data in the array
    ReDim cmodels(0 To m) As String

    'you can also use this if you want to save all information in the variable
    cmodels(2) = "test"
    ReDim Preserve cmodels(0 To m) As String

    'this will still keep "test"
    Debug.Print "With redim preserve, the value is: " & cmodels(2)

    'using just 'redim'
    ReDim cmodels(0 To m) As String
    Debug.Print "with just redim, the value is: " & cmodels(2)



End Sub

Also note that using Redim Preserve frequently (such as a loop) can be an operation which takes some time.

回答2:

Dim cmodels() As String
'...
ReDim cmodels(0 to m)

来源：https://stackoverflow.com/questions/18409519/creating-an-array-variable-with-a-variable-number-of-elements

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arrays

vba

variables

dynamic

constants