问题
I am trying to make a program that will read in a number and then output every digit of that number in a list. However, most of the things look fine until I try with number 8 and 9. The program only output \b \t instead.
if the input number contains 8 or 9, and in the same time there are other numbers, for example 283, it will print normally. Otherwise if there is only 8 or 9, such as8, 99, then it will give me that binary representation of 8 and 9 (if I remember correctly).
My program is as below:digitize(0)-> 0;digitize(N) when N < 10 -> [N];digitize(N) when N >= 10 -> digitize(N div 10)++[N rem 10].
回答1:
The function returns the expected list, but the shell shows lists of numbers which are ASCII-codes of characters as strings (because that's just what strings are in Erlang; there's no special string type). You can see it by just entering [8, 8] (e.g.) at the prompt and disable this behavior by calling shell:strings(false) (and shell:strings(true) when you need the normal behavior again).
回答2:
Strings in Erlang are no separate type but a list of numbers. List printing has a heuristic to detect when it might be a string. If it thinks it's a string it will be printed as such. \b is the backspace character and \t is the tab character which are ASCII codes 8 and 9
See also:
Description what a string means
Erlang escape sequences
Explanation of this in LYSE
来源：https://stackoverflow.com/questions/32670978/problems-in-printing-each-digit-of-a-number-in-erlang