Column alias not recognized in WHERE-statement

百般思念 提交于 2019-12-12 11:25:01

问题


I have a strange 'problem' with one of my created queries. Given the next query:

 SELECT 
 ID,
 DistanceFromUtrecht,
 (
  SELECT
   (MAX(DateUntil) - (ReleaseDays * 60 * 60 * 24))
  FROM
   PricePeriod
  WHERE
   PricePeriod.FK_Accommodation = Accommodation.ID
 ) AS LatestBookableTimestamp
FROM
 Accommodation
WHERE
 LatestBookableTimestamp < UNIX_TIMESTAMP()

phpMyAdmin keeps throwing an error about not having a column named 'LatestBookableTimestamp', even allthough I've a column, retreived by a subquery, that alias. I've also tried it selecting every column with the tableprefix. This didn't work eighter. Finally I've selected all columns by a table-alias and I gave the table an alias. All with no luck.

Can someone tell me what I'm doing wrong? I've even searched for some resources to see if I'm not mistaken, but in many cases authors on the internet use the same syntax as I do.


回答1:


Use HAVING

HAVING
  LatestBookableTimestamp < UNIX_TIMESTAMP()

On a side note, you're using a dependednt subquery, which is a bad idea performance wise.

Try like this:

SELECT 
  a.ID,
  a.DistanceFromUtrecht,
  pp.LatestBookableTimestamp
FROM
  Accommodation AS a
INNER JOIN (
  SELECT
    FK_Accommodation,
    MAX(DateUntil) - (ReleaseDays * 60 * 60 * 24) AS LatestBookableTimestamp
  FROM 
    PricePeriod 
  GROUP BY 
    FK_Accommodation
) AS pp    
ON pp.FK_Accommodation = a.ID    
WHERE
  pp.LatestBookableTimestamp < UNIX_TIMESTAMP()



回答2:


You can't use a column alias in the WHERE clause.
MySQL (and SQL Server) will allow column alias use in the GROUP BY, but it's not widely supported. ORDER BY is the most consistently supported place that supports column alias referencing.

Use:

   SELECT a.id,
          a.distancefromutrecht,
          b.LatestBookableTimestamp
     FROM ACCOMMODATION a
LEFT JOIN (SELECT pp.fk_accommodation,
                  MAX(DateUntil) - (ReleaseDays * 60 * 60 * 24) AS LatestBookableTimestamp
             FROM PRICEPERIOD pp
         GROUP BY pp.fk_accommodation) b ON b.fk_accommodation = a.id
    WHERE b.LatestBookableTimestamp < UNIX_TIMESTAMP()



回答3:


You would need to take the original query, without the where clause, and turn that into a sub query.

select * from (
 SELECT ID, DistanceFromUtrecht, 
 ( 
  SELECT 
   (MAX(DateUntil) - (ReleaseDays * 60 * 60 * 24)) 
  FROM 
   PricePeriod 
  WHERE 
   PricePeriod.FK_Accommodation = Accommodation.ID 
 ) AS LatestBookableTimestamp 
FROM 
 Accommodation 
) a
WHERE 
 LatestBookableTimestamp < UNIX_TIMESTAMP() 



回答4:


select a.ID, 
    a.DistanceFromUtrecht, MaxDateUntil - (ReleaseDays * 60 * 60 * 24) AS LatestBookableTimestamp 
from (
    SELECT FK_Accommodation, MAX(DateUntil) as MaxDateUntil
    FROM PricePeriod 
    group by FK_Accommodation
) ppm
inner join Accommodation a on ppm.FK_Accommodation = a.ID 
where MaxDateUntil - (ReleaseDays * 60 * 60 * 24) < UNIX_TIMESTAMP() 


来源:https://stackoverflow.com/questions/3550435/column-alias-not-recognized-in-where-statement

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