问题
I am trying to write a custom management command in django like below-
class Command(BaseCommand):
def add_arguments(self, parser):
parser.add_argument('delay', type=int)
def handle(self, *args, **options):
delay = options.get('delay', None)
print delay
Now when I am running python manage.py mycommand 12 it is printing 12 on console. Which is fine.
Now if I try to run python manage.py mycommand then I want that, the command prints 21 on console by default. But it is giving me something like this-
usage: manage.py mycommand [-h] [--version]
[-v {0,1,2,3}]
[--settings SETTINGS]
[--pythonpath PYTHONPATH]
[--traceback]
[--no-color]
delay
So now, how should I make the command argument "not required" and take a default value if value is not given?
回答1:
One of the recipes from the documentation suggests:
For positional arguments with nargs equal to
?or*, thedefaultvalue is used when no command-line argument was present.
So following should do the trick (it will return value if provided or default value otherwise):
parser.add_argument('delay', type=int, nargs='?', default=21)
Usage:
$ ./manage.py mycommand
21
$ ./manage.py mycommand 4
4
回答2:
You can use the dash syntax for optional keyword arguments:
class Command(BaseCommand):
def add_arguments(self, parser):
parser.add_argument("-d", "--delay", type=int)
def handle(self, *args, **options):
delay = options["delay"] if options["delay"] else 21
print(delay)
Use:
$ python manage.py mycommand -d 4
4
$ python manage.py mycommand --delay 4
4
$ python manage.py mycommand
21
Docs:
https://docs.djangoproject.com/en/2.2/howto/custom-management-commands/#s-accepting-optional-arguments
Simple explanation:
https://simpleisbetterthancomplex.com/tutorial/2018/08/27/how-to-create-custom-django-management-commands.html#handling-arguments
来源:https://stackoverflow.com/questions/35635128/how-to-make-a-django-custom-management-command-argument-not-required