问题
Im trying to generate a 2d array using a random generator. basically, each column should contain a random value between 1-50 that is not repeated but the problem is, I can't get a repeat value on the same row, or any other row or column in the program. In other words, each I integer should only display once. My objects were created via linked list and I will probably integrate the algorthim in there once I figure it out but for now, heres what I did.
int[] array = new int[50];
for(int i=1;i<=9;i++)
{
int[] grades = new int[5];
for(int j=0;j<=4;j++)
{
int unique = gen.nextInt(50)+1;
grades[j] = unique;
}
list.add(new Student(i, grades));
}
System.out.println(list);
My output:
Student1: 20 49 45 16 13
Student2: 28 10 11 30 6
Student3: 13 25 37 31 49
Student4: 8 23 8 12 32
Student5: 22 18 35 2 7
Student6: 35 8 16 23 36
Student7: 35 3 15 42 2
Student8: 43 12 44 2 35
Student9: 12 21 36 23 12
So my issue is this. How can I implement the random gen without repeating values. Normally I would try a collection list by now, but I'm trying to do this using java.util.Random Personally, I would do this a different way but I'm instructed. Thank you
回答1:
Here's what I would do:
Take an ArrayList of numbers 1-50, then use Collections.shuffle on the list.
回答2:
You could check if the number is unique before accepting it. For example you could try something like the following:
int count=0;
List<Integer> list=new ArrayList<Integer>();
while(count<50){
int num=random.nextInt(50);
if(!list.contains(num)){
list.add(num);
++count;
}
}
来源:https://stackoverflow.com/questions/16284894/java-random-generator-without-repeat