问题
How do I fix the following query? My attempt to alias the result of the SELECT query into table tmp does not work.
INSERT INTO vote_counts (list_id, node_id, num_down_votes)
(SELECT vl.list_id, vl.node_id, COUNT(*) AS c
FROM vote_logs vl
WHERE vl.node_id=2442703 AND vl.agree_type='DOWN_VOTE'
GROUP BY vl.list_id) tmp
ON DUPLICATE KEY UPDATE num_down_votes = tmp.c;
The vote_counts table has a unique key constraint on (list_id, node_id).
回答1:
If I'm not mistaken, this should work:
INSERT INTO vote_counts (list_id, node_id, num_down_votes)
SELECT vl.list_id, vl.node_id, COUNT(*) AS c
FROM vote_logs vl
WHERE vl.node_id=2442703 AND vl.agree_type='DOWN_VOTE'
GROUP BY vl.list_id
ON DUPLICATE KEY UPDATE num_down_votes = vl.c;
If vl.c doesn't work, you may need to use Count(vl.*) since it's an alias -- not sure, would have to test it.
--EDIT
Perhaps using a subquery will resolve this issue:
INSERT INTO vote_counts (list_id, node_id, num_down_votes)
SELECT list_id, node_id, c
FROM (
SELECT vl.list_id, vl.node_id, COUNT(*) AS c
FROM vote_logs vl
WHERE vl.node_id=2442703 AND vl.agree_type='DOWN_VOTE'
GROUP BY vl.list_id
) tempTable
ON DUPLICATE KEY UPDATE num_down_votes = tempTable.c;
Good luck.
来源:https://stackoverflow.com/questions/14533091/mysql-how-to-store-results-of-group-by-for-use-in-on-duplicate-key-update