问题
i want to make a beautiful URL from a URL like this:
http://example1.com/cimage/webroot/img.php?src=http://example.com/img1.jpg&w=600&h=800&q=60&sharpen&crop-to-fit
So the result URL must be somthing like this:
http://example1.com/cimage/webroot/img.php/http://example2.com/img1.jpg/600*800/60/sharpen/crop-to-fit
Now my problem create a regex for use in apache mod_rewrite. help me please. thanks...
回答1:
Based on the discussion in the comments, this is the solution:
RewriteRule ^img.php/(https?):/+(.+?(?:\.jpg|\.png))/(\d+)/(\d+)/(\d+)/?([^\/]*)/?([^\/]*)/?([^\/]*)$ img.php?src=$1://$2&w=$3&h=$4&q=$5&$6&$7&$8
Demo
The logic here is to match img.php/ at the start of the string, then either http or https, :, one or more /s, the host and file name, then the various parameters for size, quality, etc.
Another way to handle this without the complicated regex is to do a simple catch-all rule like this:
RewriteRule ^img.php\/(.+) img.php?url=$1
Then you can do the parsing in PHP, mostly using simpler operations like explode() in the PHP code. This approach makes sense especially if there might be additional operations/parameters; otherwise, your regex starts to have a lot of capturing groups, making it hard to read and maintain.
来源：https://stackoverflow.com/questions/28038590/apache-mod-rewrite-complex-url-regex