How to divide integer by a constant integer with right shift operators? [duplicate]

问题

This question already has answers here:

How can I multiply and divide using only bit shifting and adding? (13 answers)

Division by a constant using shifts and adds/subtracts (3 answers)

Closed 6 years ago.

I'm interested how to do this, because I just found out you can do integer multiplication easily, by using left shift operators:

x * 25 = (x << 4) + (x << 3) + x

Where the sum of base 2 powers equals to 25: 2^4+2^3+2^0 = 25

How does x / 25 work out with right shifts?

Edit: I'm not going to replace division and multiplication in my programs by these shift operators in hope of speed boost ;)

来源：https://stackoverflow.com/questions/16088086/how-to-divide-integer-by-a-constant-integer-with-right-shift-operators